使用以下命令从列表中创建目录:
import os
cwd = os.getcwd()
folders = ['file1','file2','file3']
for folder in folders:
os.mkdir(os.path.join(cwd,folder))
还想在每个文件中添加三个子目录,例如 ['sub1','sub2','sub3']
尝试过类似的方法(以及其他简单的方法)但没有成功:
import os
cwd = os.getcwd()
folders = ['file1','file2','file3']
subfolders = ['sub1','sub2','sub3']
for folder in folders:
os.makedirs('os.path.join(cwd,folder/subfolders/)')
有什么想法吗?谢谢!
最佳答案
import os
cwd = os.getcwd()
folders = ['file1','file2','file3']
subfolders = ['sub1','sub2','sub3']
for folder in folders:
os.mkdir(os.path.join(cwd, folder))
# Create sub-folders.
for sub in subfolders:
os.mkdir(os.path.join(cwd, folder, sub))
关于python - 如何从列表中创建目录并在 python 中包含子目录列表?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37632207/