python按顺序读取多个文件

Question

我的文件顺序如下:

H2_000.csv， H2_001.csv， H2_002.csv， H2_003.csv， H2_004.csv， H2_005.csv。

import glob

path = 'path/H2_*.csv'
files=glob.glob(path)
for file in files:
    f=open(file, 'r')
    print f

output
open file 'path/H2_003.csv', mode 'r' at 0x7f3ce9eca150,
open file 'path/H2_000.csv', mode 'r' at 0x7f3ce9eca1e0,
open file 'path/H2_004.csv', mode 'r' at 0x7f3ce9eca150,
open file 'path/H2_001.csv', mode 'r' at 0x7f3ce9eca1e0,

但这会随机读取文件， 我希望文件按顺序打开。 谁能帮我。谢谢!

Answer 1

您需要做的就是对文件列表进行排序(并且始终使用 with)

import glob

path = 'path/H2_*.csv'
files=glob.glob(path)
for file in sorted(files):
    with open(file, 'r') as f:
        print f