python - 以字符串格式返回的字符串数平均值

Question

以下是一些测试:

输入:“零九五二”

输出:“四”

输入:“四六二三”

输出:“三”

这是我的代码，直到最后一步我需要按值反向查找键，我不知道该怎么做。有什么建议吗？

def average_string(s):
    num_dic = {'zero': 0, 'one': 1, 'two': 2, 'three': 3, 'four': 4, 'five': 5, 
    'six': 6, 'seven': 7, 'eight': 8, 'nine': 9}
    str_split = s.split()
    int_values = []
    for key, val in num_dic.items():
        if key in str_split: 
            int_values.append(val)
            int_avg = int(sum(int_values) / len(int_values))
    return int_avg

Answer 1

你可以试试这个:

num_dic = {'zero': 0, 'one': 1, 'two': 2, 'three': 3, 'four': 4, 'five': 5, 'six': 6, 'seven': 7, 'eight': 8, 'nine': 9}

s = "zero nine five two"

new_dict = {b:a for a, b in num_dic.items()}

average = sum(num_dic[i] for i in s.split())/float(len(s.split()))

final_average = new_dict[average]

输出:

four