python - 如何从utcnow中提取日、月、年？

Question

我有以下变量:time_created = datetime.utcnow()

如何从 time_created 创建仅包含 Y、M、d 的 time_created_day 变量

像这样datetime.datetime(2017, 11, 7)

我有以下解决方案:

from datetime import date

time_created_day = date(time_created.year, time_created.month, time_created. day)

这是最好的方法吗？

Answer 1

使用datetime.utcnow().date()

datetime.utcnow().date()
datetime.date(2017, 11, 7)

添加到答案

日期时间对象始终包含年、月、日以及小时、分钟、秒和微秒。它是日期和时间对象包含的内容的组合，请参阅 datetime Objects

from datetime import datetime

# this is your datetime object
time_created = datetime.utcnow()

# when you want to see it formatted as Y,M,D call the date method
date_created = time_created.date()

time_created
date_created

输出:

datetime.datetime(2017, 11, 7, 23, 43, 43, 761750)
datetime.date(2017, 11, 7)`