python - 找到单词中最常见的字母；按字母顺序

Question

程序输入是一个字符串。我想要从这个字符串中找到最常见的字母。如果有多个字母具有相同的频率，我将返回拉丁字母表中第一个字母

代码:

def most_Wanted(text="Hello Oman"):
    lst = [x for x in text.replace(" ","").lower() if x.isalpha]
    count = {}
    for letter in lst:
        if letter in count:
            count[letter] += 1
        else:
            count[letter] = 1
    count = list(count.items())
    sorted(count, key=lambda x: (-x[1],x[0]))
    print(count[0][0])

预期:

l #though o and l appear 3 times, l is before o in the latin alphabet

输出:

h #there seems to be an error in the sorting as the first pair of tuples in the list always seems to be the first letter of the text?

任何关于美化代码的建议都很好，尽管我宁愿现在不使用模块，这样我就可以学习核心Python。谢谢:)

Answer 1

主要问题是 sorted 返回一个新列表，它不是就地的。

您应该重新分配其返回值，或使用.sort():

count = sorted(count, key=lambda x: (-x[1],x[0]))

或

count.sort(key=lambda x: (-x[1],x[0]))

线路也有问题

lst = [x for x in text.replace(" ","").lower() if x.isalpha]

if x.isalpha 总是返回 True 因为它只是引用函数而不是实际调用它。应改为

lst = [x for x in text.replace(" ","").lower() if x.isalpha()]