注意:它没有固定网址。意味着不可能总是看到这个网址。我想要适用于所有网址的代码。
例如,http://januapp.com/demo/search.php?search=aaa
http://januapp.com/demo/search.php?other=aaa
现在我想将其更改为
http://januapp.com/demo/search.php?search=bbb http://januapp.com/demo/search.php?other=bbb
我不知道该怎么办?
我试过了
import optparse
import requests
import urlparse
parser = optparse.OptionParser()
parser.add_option("-t","--Host", dest="Target", help="Please provide the target", default="true")
options, args = parser.parse_args()
url = options.Target
xss = []
xss.append("bbb")
try:
url2 =urlparse.urlparse(url)
print url2
url3 = urlparse.parse_qs(url2.query)
parametervalue = [key for key, key in url3.iteritems()] #[['aaa']]
parsed = parametervalue.append(xss[0])
print parsed
finalurl = urljoin(url, parsed)
print finalurl
except Exception as e:
print e
所以当我通过这个
xss3.py -t http://januapp.com/demo/search.php?search=aaa
cmd 下面出现错误
ParseResult(scheme='http', netloc='januapp.com', path='/demo/search.php', params='', query='search=aaa', fragment='')
None
name 'urljoin' is not defined
查看无
这就是问题所在
我使用的是Python2.7。
非常感谢。希望您能解决这个问题。
最佳答案
你可以尝试用这种方法。
url = 'http://januapp.com/demo/search.php?search=aaa'
# First get all your query params
arr = url.split('?')
base_url = arr[0] # This is your base url i.e. 'http://januapp.com/demo/search.php'
params = arr[1] # here are your query params ['search=aaa']
# Now seprate out all the query parameters and their values
arr2 = params.split("=") # This will give you somrthing like this : ['search', 'aaa'], the the value will be next to the key
# This is a dictonary to hold the key value pairs
param_value_dict = {} # {'search': 'aaa'}
for i, str in enumerate(arr2):
if i % 2 == 0:
param_value_dict[str] = arr2[i + 1]
# now if you want to chnage the value of search from 'aaa' to 'bbb', then just change it in the dictonary
param_value_dict['search'] = 'bbb'
# now form the new url from the dictonary
new_url = base_url + '?'
for param_name, param_value in param_value_dict.items():
new_url = new_url + param_name + "=" + param_value + "&"
# remove the extra '&'
new_url = new_url[:len(new_url) - 1]
print(new_url)
关于python - 如何改变python中参数的值?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49108465/