<分区>
我正在尝试使用 mysqli_query 从表中获取数据。 当我使用以下命令时，它工作正常:
$hostname = "********";
$username = "*******";
$password = "********";
$databaseName = "**************";
$dbConnected = mysqli_connect($hostname, $username, $password, $databaseName);
当我尝试使用上述代码包含文件时 include('../htconfig/dbConfig.php');然后我没有得到任何结果:
...“0 个结果”
<?php
include('../htconfig/dbConfig.php');
$dbConnected = mysqli_connect($db['hostname'], $db['username'], $db['password'], $db['databaseName']);
if(!$dbConnected) {
die('Connect Error (' . mysqli_connect_errno() . ') '
. mysqli_connect_error());
}
echo 'Success... ' . mysqli_get_host_info($dbConnected) . "\n". "<br>";
mysqli_set_charset($dbConnected, "utf8");
$tPerson_SQLselect = "SELECT ";
$tPerson_SQLselect .= "ID, Salutation, FirstName, LastName, CompanyID ";
$tPerson_SQLselect .= "FROM ";
$tPerson_SQLselect .= "tPerson ";
$result = mysqli_query($dbConnected, $tPerson_SQLselect);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
echo "Salutation: ".$row["Salutation"]. "-FirstName: ".$row["FirstName"]." ".$row["LastName"]." -CompanyID: ".$row["CompanyID"]. "<br>";
}
} else {
echo "0 results";
}
mysqli_close($dbConnected);
?>
我找不到我的错误.. 请帮忙!
dbConfig.php 文件:
<?php
$db = array(
'hostname' => '*****',
'username' => '*****',
'password' => '*****',
'database' => '*****',
);
?>