python - Telegram 类型错误 : the first argument must be callable

Question

我正在尝试在 Telegram 中进行自动发布安排。它第一次运行，但在尝试循环后出现错误:

TypeError: the first argument must be callable

我的代码:

import time
import schedule
from pyrogram import Client, ReplyKeyboardMarkup, InlineKeyboardMarkup, InlineKeyboardButton
from pyrogram.api import functions, types
from pyrogram.api.errors import FloodWait


person1 = Client(
    session_name="*cenzored*",
    api_id=*cenzored*,
    api_hash="*cenzored*"
)

person2 = Client(
    session_name="*cenzored*",
    api_id=*cenzored*,
    api_hash="*cenzored*"
)
wick.start()

def Publish(session,dat,msgid,session_name):
    try:
        session.start()
        print("[%s]Posting..." % (session_name))
        session.send(
            functions.messages.GetBotCallbackAnswer(
                peer=session.resolve_peer("*cenzored*"),         
                msg_id=msgid,
                data=b'publish %d' % (dat)
            )
        )
        session.idle()
    except:
        print("Crashed,starting over")

schedule.every(0.3).minutes.do(Publish(person1,142129,12758, 'Dani')) // Here is the line is crashing.
schedule.every(0.3).minutes.do(Publish(person2,137351,13177, 'Wick'))

while 1:
    schedule.run_pending()
    time.sleep(1)

回溯:

Pyrogram v0.7.4, Copyright (C) 2017-2018 Dan Tès <https://github.com/delivrance>
Licensed under the terms of the GNU Lesser General Public License v3 or later (LGPLv3+)

[person1]Posting...
3: 2018-06-16 12:07:26.529829 Retrying <class 'pyrogram.api.functions.messages.get_bot_callback_answer.GetBotCallbackAnswer'>
4: 2018-06-16 12:07:42.041309 Retrying <class 'pyrogram.api.functions.messages.get_bot_callback_answer.GetBotCallbackAnswer'>
Crashed,starting over
Traceback (most recent call last):
  File "C:\Users\343df\OneDrive\Desktop\Maor\python\tele\tele.py", line 35, in <module>
    schedule.every(0.3).minutes.do(Publish('ss',dani,140129,12758, 'Dani'))
  File "C:\Program Files (x86)\Python36-32\lib\site-packages\schedule\__init__.py", line 385, in do
    self.job_func = functools.partial(job_func, *args, **kwargs)
TypeError: the first argument must be callable

基本上我的问题是在第一次之后没有运行(TypeError:第一个参数必须可调用)并且计划每 0.3 秒运行一次。

Answer 1

根据[ReadTheDocs]: do(job_func, *args, **kwargs) ，您不必调用 Publish，而只需传递它，后跟其参数列表(调用将由schedule框架执行):

schedule.every(0.3).minutes.do(Publish, person1, 142129, 12758, "Dani")
schedule.every(0.3).minutes.do(Publish, person2, 137351, 13177, "Wick")