python - 为了允许非 dict 对象被序列化，将 safe 参数设置为 False

Question

我使用 websocket 前端( Angular )后端(Django)创建实时聊天应用程序..我想将消息存储到数据库(mySql)..当我尝试将消息数组从 Angular 存储到 django 时..它给了我错误像 500 内部服务器 Eroor 一样，为了允许非 dict 对象被序列化，将 safe 参数设置为 False。 我在列表数组中发送消息数据..那么出了什么问题？

模型.py

class msg(models.Model):
    name = models.ForeignKey(User, on_delete=models.CASCADE)
    receiver = models.CharField(max_length=20)
    text = models.CharField(max_length=1200)
    myDate = models.DateTimeField()

序列化器.py

class MesSerializer(serializers.ModelSerializer):
    name = serializers.SlugRelatedField(many=False, slug_field='name', queryset=User.objects.all())
    receiver = serializers.SlugRelatedField(many=False, slug_field='name', queryset=User.objects.all())
    class Meta:
        model = msg
        fields = '__all__'

查看.py

class msg_list(APIView):
    def get(self, request, format=None):
        mes = msg.objects.all()
        serializer = MesSerializer(mes, many=True)  # convert into JSON
        return Response(serializer.data)

    def post(self, request, formate = None):
        data = JSONParser().parse(request) #type list
        serializer = MesSerializer(data= data, many = True) #type list
        if serializer.is_valid():
            serializer.save()
            return JsonResponse(serializer.data, status=201)
        return JsonResponse(serializer.errors, status=400)

当我打开消息 api 时:

Answer 1

序列化前不需要解析请求。只需传递 request.data 作为序列化器参数:

def post(self, request, formate = None):
    serializer = MesSerializer(data=request.data, many=True) #type list
    if serializer.is_valid():
        serializer.save()
        return JsonResponse(serializer.data, status=201)
    return JsonResponse(serializer.errors, status=400)

UPD

receiver 是 CharField，因此您不能对其使用 SlugRelatedField。只需在序列化器中使用默认的 CharField 即可:

class MesSerializer(serializers.ModelSerializer):
    name = serializers.SlugRelatedField(many=False, slug_field='name', queryset=User.objects.all())
    class Meta:
        model = msg
        fields = '__all__'