python - 在Python中打印小数点到8位精度？

Question

以下代码打印各种精度的小数，但恢复为超过 7 位的科学记数法。我需要在 UI 中显示至少 8 个位置的字符串宽度。

如何获得 8 位精度的字符串化小数？

from decimal import *
getcontext().prec = 8 # set precision to 8 decimal points. 
getcontext().rounding = "ROUND_DOWN" # alway round down 

# stringified zero of various precisions

zw = ['0', '0.0', '0.00', '0.000000', '.00000000', '0.00000000', '0.000000000000']

for n in range(0,len(zw)): 
    zstr = zw[n]                # stringified zero 
    zdec = Decimal(zstr)        # decimalized zero
    print (zstr, ":", zdec) # compare stringified and decimalized zero

Answer 1

尝试:

from decimal import *
getcontext().prec = 8 # set precision to 8 decimal points. 
getcontext().rounding = "ROUND_DOWN" # alway round down 

# stringified zero of various precisions

zw = ['0', '0.0', '0.00', '0.000000', '.00000000', '0.00000000', '0.000000000000']

for zstr in zw: 
    zdec = Decimal(zstr)        # decimalized zero
    print ('{} : {:.8f}'.format(zstr, zdec)) # compare stringified and decimalized zero

打印:

0 : 0.00000000
0.0 : 0.00000000
0.00 : 0.00000000
0.000000 : 0.00000000
.00000000 : 0.00000000
0.00000000 : 0.00000000
0.000000000000 : 0.00000000