我正在开发带有嵌入视频的网站(Django 2.1),我需要使用外部脚本填充我的数据库。我有两个表,一个是父表(视频),另一个是子表(缩略图),其中是 imageField。我需要从 url 下载缩略图并以编程方式将图像插入到 ImageField 中。我和这个问题斗争了两天。我已经在 stackoverflow 上阅读了一些建议,但对我来说没有任何作用,我在这里放弃。有人可以帮我吗?
这是我的模型的一部分:
#my models.py
class Video(models.Model):
title = models.CharField(max_length=255)
slug = models.SlugField(max_length=255, unique = True)
video_url = models.URLField(max_length=255, unique = True)
class Thumbnail(models.Model):
name = models.CharField(max_length=50)
thumb = models.ImageField(upload_to='thumb/', null=True, blank=True)
thumb_resolution = models.CharField(max_length=50, null=True, blank=True)
videos = models.ForeignKey(Video, on_delete=models.CASCADE, related_name='thumbnails')
这是我的下载代码的简化版本,我尝试了几种不同的方法,但大多数尝试都没有错误地结束,但 MEDIA 文件夹中没有文件。但是我的视频和缩略图之间的 OneToMany 关系已成功创建。
import requests
from io import BytesIO
from PIL import Image
os.environ.setdefault("DJANGO_SETTINGS_MODULE", "video.settings")
import django
django.setup()
from django.core.files import File
from django.core.files.base import ContentFile
from mainSite.models import Video, Thumbnail
def download(url):
try:
r = requests.get(url)
if not r.status_code == 200:
raise Exception('file request failed with status code: ' + str(r.status_code))
return (r.content)
except Exception as ex:
print (ex)
return ('error')
VIDEO_URL = "https://videowebsite.com/video/43332"
VIDEO_THUMBS = ["https://videowebsite.com/thumb/1.jpg","https://videowebsite.com/thumb/2.jpg"]
# title, slug , video_url exist in my code
add_video = Video(title=title,slug=slug,video_url=video_url)
add_video.save()
for image in VIDEO_THUMBS:
get_file = download(image)
file_name = image.split('/')[-1]
if get_file != 'error' and len(get_file) > 0:
# I tried several different ways here but none of them work.
f = BytesIO(get_file)
Thumbnail(name=file_name, thumb=File(f), videos = add_video).save()
#No error but image does not exist on server in MEDIA folder
#--------------------------------------------
with Image.open(get_file) as img:
Thumbnail(name=file_name, thumb=ContentFile(img), videos = add_video).save()
# ValueError: embedded null byte
#--------------------------------------------
Thumbnail(name=file_name, thumb=File(get_file), videos = add_video).save()
# No error but image does not exist on server
#--------------------------------------------
with Image.open(get_file) as img:
Thumbnail(name=file_name, thumb=File(img), videos = add_video).save()
# No error but image does not exist on server
#--------------------------------------------
f = BytesIO(get_file)
with Image.open(f) as img:
Thumbnail(name=file_name, thumb=File(img), videos = add_video).save()
#Again no error but images does not exist
else:
print('error')
我真的迷失了这里,有人可以告诉我我在这里做错了什么吗?大多数情况下没有错误,父表和子表之间的关系已成功创建,但图像未上传到 MEDIA/thumb 文件夹中。预先非常感谢您。
最佳答案
解决方案:
from io import BytesIO
from django.core.files.base import ContentFile
from PIL import Image
for image in VIDEO_THUMBS:
get_file = download(image)
file_name = image.split('/')[-1]
# please read https://pillow.readthedocs.io/en/3.1.x/handbook/image-file-formats.html
# for available formats.
extension = 'jpeg'
f = BytesIO(get_file)
out = BytesIO()
image = Image.open(f)
image.save(out, extension)
t = Thumbnail(<all fields except thumb>)
t.thumb.save(file_name, ContentFile(out.getvalue()), save=False)
t.save()
- 将文件保存到内存[变量
out
] - 使用 Django 的
ContentFile
类使用内存中的文件内容进行初始化
编辑:您不需要StringIO
,BytesIO
将完成这项工作。
关于python - Django - 使用外部脚本从 url 下载图像并将其插入 imageField,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52101717/