我有一个非常简单的查询,不确定我在这里做错了什么。
我的数据库调用没有收到我期望的 insert id
。
表格:
存储过程:
CREATE DEFINER=`root`@`localhost` PROCEDURE `addCustomerProduct`(IN in_customerID INT, in_productID INT)
BEGIN
INSERT INTO order_customer_product (customerID, productID, retailAmountAtPurchase, faceValue)
SELECT
in_customerID,
in_productID,
p.retail,
p.faceValue
FROM
products as p
WHERE
p.productID = in_productID;
END
PHP:
public function addProduct($data, $userID)
{
// Do we already have a pending order for this user?
$orderID = $this->doesOrderExist($userID);
// We had no order, lets create one
if (!$orderID) {
$orderID = $this->createOrder($userID);
}
/**
* Insert the customer product.
* This relates a denomination to a customer.
*/
$customerProductID = $this->addCustomerProduct($data);
// Add this customer product to the order
$this->addProductToOrder(array("customerProductID" => $customerProductID, "orderID" => $orderID));
// Return
return $customerProductID;
}
/**
* Description: Add a customer product / reward
* Page: client/add_reward
*/
public function addCustomerProduct($data){
$procedure = "CALL addCustomerProduct(?,?)";
$result = $this->db->query($procedure, $data);
return $this->db->insert_id();
}
有问题的行是:$customerProductID = $this->addCustomerProduct($data);
。
正在向表中插入一条新记录,并且该表有一个 PK/AI
。数据正常,但 0
作为 $customerProductID
返回。
从 select 语句插入可能不会返回 insert ID
吗?
更新@Ravi-
更新 2:
我创建了一个单独的方法并对要发送的查询和数据进行硬编码。
它很好地添加了记录,AI 上升,0
作为 last id
返回。
public function test(){
$procedure = "CALL addCustomerProduct(?,?)";
$result = $this->db->query($procedure, array("customerID" => 1, "productID" => 20));
echo $this->db->insert_id();
}
还重新启动了 MySQL 服务器以确保那里没有发生任何奇怪的事情。
此外,更新了 SP 以在不使用选择的情况下将随机数据插入表中。
CREATE DEFINER=`root`@`localhost` PROCEDURE `addCustomerProduct`(IN in_customerID INT, in_productID INT)
BEGIN
INSERT INTO order_customer_product (customerID, productID, retailAmountAtPurchase, faceValue)
VALUES(8,2,'4.55',25);
END
更新 3:
插入后,我将打印出最后运行的查询以及结果。您会注意到有 1 个受影响的行(正在插入),但 insert_id
仍为 0。
CALL addCustomerProduct('8','33')
CI_DB_mysqli_result Object
(
[conn_id] => mysqli Object
(
[affected_rows] => 1
[client_info] => mysqlnd 5.0.12-dev - 20150407 - $Id: b396954eeb2d1d9ed7902b8bae237b287f21ad9e $
[client_version] => 50012
[connect_errno] => 0
[connect_error] =>
[errno] => 0
[error] =>
[error_list] => Array
(
)
[field_count] => 0
[host_info] => Localhost via UNIX socket
[info] =>
[insert_id] => 0
[server_info] => 5.6.35
[server_version] => 50635
[stat] => Uptime: 1637 Threads: 3 Questions: 508 Slow queries: 0 Opens: 113 Flush tables: 1 Open tables: 106 Queries per second avg: 0.310
[sqlstate] => 00000
[protocol_version] => 10
[thread_id] => 25
[warning_count] => 0
)
[result_id] => 1
[result_array] => Array
(
)
[result_object] => Array
(
)
[custom_result_object] => Array
(
)
[current_row] => 0
[num_rows] =>
[row_data] =>
)
更新 4:
根据我所做的一些研究,除非您使用 mysqli 方法,例如 $this->db->insert()
,否则它不会向您提供最后的插入 ID .
我将尝试找出 Ravi 的建议,但代码点火器似乎不允许显示的示例。至少我现在知道我并不疯狂,这只是不正常的行为,除非你使用 ``insert` 方法而不是存储过程。
最佳答案
This answer可能会解释为什么您现有的代码不起作用。引用:
CodeIgniter's
insert_id()
will only return an ID of aninsert()
. Unless you are executing something like$this->db->insert('table', $data);
before calling the function it will not be able to return an ID.
MySQL 的 LAST_INSERT_ID();
应该在这里帮助你(假设你有权改变存储过程定义)。将其更改为:
CREATE DEFINER=`root`@`localhost` PROCEDURE `addCustomerProduct`(
IN in_customerID INT, in_productID INT, OUT out_customerProductID INT)
BEGIN
INSERT INTO order_customer_product (
customerID, productID, retailAmountAtPurchase, faceValue)
VALUES(8,2,'4.55',25);
SELECT LAST_INSERT_ID() INTO out_customerProductID;
END
然后使用类似下面的方法获取输出参数值:
public function addCustomerProduct($data) {
$procedure = "CALL addCustomerProduct("
. $this->db->escape($data["customerID"]).", "
. $this->db->escape($data["productID"]).", "
. "@customerProductID);"
$this->db->query($procedure);
$query = $this->db->query("SELECT @customerProductID AS customerProductID");
if($query->num_rows() > 0)
return $query->result()->customerProductID;
else
return NULL;
}
如果上述方法不起作用,请尝试添加 $this->db->trans_start();
和 $this->db->trans_complete();
在存储过程调用之前和之后确保事务已提交。
关于php - MySQL 存储过程没有返回插入 ID?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48247398/