python - 无法使用套接字获取所需内容

Question

我正在尝试从 here 获取可见内容使用 socket 但不幸的是，我在执行脚本时遇到错误。由于我对使用 socket 编写代码非常陌生，所以我不明白我哪里出了问题。

我的代码:

import socket

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host_ip = socket.gethostbyname('data.pr4e.org')
s.connect((host_ip,80))
cmd = "GET http://data.pr4e.org/romeo.txt HTTP/1.0\n\n".encode()
s.send(cmd)

while True:
    data = s.recv(1024)
    if (len(data) <1 ):
        break
    print(data.decode())
s.close()

我遇到的错误:

400 Bad Request

Your browser sent a request that this server could not understand.

Answer 1

通过将 \r\n\r\n 添加到请求命令的末尾，而不是原来的 \n\n，我能够获得所需的结果>:

import socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((socket.gethostbyname('data.pr4e.org'), 80))
s.sendall("GET http://data.pr4e.org/romeo.txt HTTP/1.0\r\n\r\n".encode())
print(s.recv(1024))

输出:

...
Content-Type: text/plain\r\n\r\nBut soft what light through yonder window breaks\nIt is the east and Juliet is the sun\nArise fair sun and kill the envious moon\nWho is already sick and pale with grief\n'