我正在使用套接字编程来发送 UDP 文本消息,并且工作正常。这是代码:
发送:
import socket
UDP_IP = "10.0.0.2"
UDP_PORT = 5005
MESSAGE = "Hello"
print "UDP target IP:", UDP_IP
print "UDP target port:", UDP_PORT
print "message:", MESSAGE
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) # UDP
sock.sendto(MESSAGE, (UDP_IP, UDP_PORT))
接收:
import socket
UDP_IP = "10.0.0.2"
UDP_PORT = 5005
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) # UDP
sock.bind((UDP_IP, UDP_PORT))
while True:
data, addr = sock.recvfrom(1024)
print "received message:", data
现在我想更改发送到列表的消息。我尝试使用pickle来做到这一点。这是代码:
发送:
import socket
import pickle
UDP_IP = "10.0.0.2"
UDP_PORT = 5005
a = []
a.append('H')
a.append('G')
MESSAGE = pickle.dumps(a)
print "UDP target IP:", UDP_IP
print "UDP target port:", UDP_PORT
print "message:", MESSAGE
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) # UDP
sock.sendto(MESSAGE, (UDP_IP, UDP_PORT))
接收:
import socket
import pickle
UDP_IP = "10.0.0.2"
UDP_PORT = 5005
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) # UDP
sock.bind((UDP_IP, UDP_PORT))
while True:
data, addr = sock.recvfrom(1024)
print "received message:", data
pickle.loads(data)
print(data)
但是我没有在接收端获得正确的列表形式。这是输出:
(1p0
S'H'
p1
aS'G'
p2
a.
(1p0
S'H'
p1
aS'G'
p2
a.
出了什么问题?
最佳答案
问题已经解决了。代码工作正常,有一个问题,因为我打印的是数据本身而不是pickle.loads(data)的输出,所以这段代码现在工作正常:
接收:
import socket
import pickle
UDP_IP = "10.0.0.2"
UDP_PORT = 5005
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) # UDP
sock.bind((UDP_IP, UDP_PORT))
while True:
data, addr = sock.recvfrom(1024)
print "received message:", data
print(pickle.loads(data))
关于python - 通过UDP发送列表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53683394/