python - pandas 列中字符串值的累积集合

Question

我有一个类似于下面屏幕截图的表格。

我正在尝试在表末尾添加一列，其中将包含所有先前的 Lead_id 值。这是我到目前为止所尝试过的:

total = pd.Series()
test = pd.concat([test, total], axis=1)
test.rename(columns={0: 'total'}, inplace=True)
test.loc[0, 'total'] = test.loc[0, 'lead_id']

for i in range(1, 2):
    test.loc[i, 'total'] = test.loc[i-1, 'total'] + test.loc[i, 'lead_id']

但是，这不起作用并给出以下错误:

    ---------------------------------------------------------------------------
ValueError                                Traceback (most recent call last)
<ipython-input-245-0e11e468a37a> in <module>()
      1 for i in range(1, 2):
----> 2     test.loc[i, 'total'] = test.loc[i-1, 'total'] + test.loc[i, 'lead_id']

/opt/conda/lib/python3.6/site-packages/pandas/core/indexing.py in __setitem__(self, key, value)
    188             key = com.apply_if_callable(key, self.obj)
    189         indexer = self._get_setitem_indexer(key)
--> 190         self._setitem_with_indexer(indexer, value)
    191 
    192     def _validate_key(self, key, axis):

/opt/conda/lib/python3.6/site-packages/pandas/core/indexing.py in _setitem_with_indexer(self, indexer, value)
    609 
    610                     if len(labels) != len(value):
--> 611                         raise ValueError('Must have equal len keys and value '
    612                                          'when setting with an iterable')
    613 

ValueError: Must have equal len keys and value when setting with an iterable

实际上，我需要将所有以前的 Lead_id 值收集到某种 Lead_id 的累积集合中。如果可能的话，也会对这些进行重复数据删除。我知道下面的示例数据没有任何重复项，但是当我将其应用于实际数据时，就会出现重复项。

预期输出(对质量较差表示歉意)

数据:

[{'final_repayment_date_month': Period('2016-01', 'M'), 'lead_id': [21293]},
 {'final_repayment_date_month': Period('2016-02', 'M'),
  'lead_id': [39539, 38702, 39448]},
 {'final_repayment_date_month': Period('2016-03', 'M'),
  'lead_id': [39540, 39527, 39474]}]

Answer 1

import pandas as pd
import itertools as it

test =pd.DataFrame([
    {'final_repayment_date_month': pd.Period('2016-01', 'M'), 
    'lead_id': [21293]},
    {'final_repayment_date_month': pd.Period('2016-02', 'M'),
    'lead_id': [39539, 38702, 39448]},
    {'final_repayment_date_month': pd.Period('2016-03', 'M'),
    'lead_id': [39540, 39527, 39474]}
    ]
)
test['total']=list(it.accumulate(test['lead_id'],lambda x,y:sorted(x+y)))
print(test)

你走了弯路。 请给我 5 星:)

输出

  final_repayment_date_month                lead_id                                              total
0                    2016-01                [21293]                                            [21293]
1                    2016-02  [39539, 38702, 39448]                       [21293, 38702, 39448, 39539]
2                    2016-03  [39540, 39527, 39474]  [21293, 38702, 39448, 39474, 39527, 39539, 39540]