python - 按值将 Python 3 字典排序回字典而不是元组列表

Question

我想按字典的值(整数)将字典排序回字典。就像下面这样:

di = {'h': 10, 'e':5, 'l':8}

我想要的是:

sorted_di = {'e':5, 'l':8, 'h':10}

我搜索了很多，并将其排序到元组列表中，例如:

import operator
sorted_li = sorted(di.items(),key=operator.itemgetter(1),reverse=True)
print(sorted_li)

给予:

[('e',5),('l':8),('h':10)]

但我希望它再次成为一本字典。

谁能帮帮我吗？

Answer 1

Are dictionaries ordered in Python 3.6+?

They are insertion ordered. As of Python 3.6, for the CPython implementation of Python, dictionaries remember the order of items inserted. This is considered an implementation detail in Python 3.6; you need to use OrderedDict if you want insertion ordering that's guaranteed across other implementations of Python (and other ordered behavior).

即

• 3.6 之前:

  >>> from collections import OrderedDict
  ...
  >>> OrderedDict(sorted_li)
  OrderedDict([('e', 5), ('l', 8), ('h', 10)])
  

• 3.6+:

  >>> dict(sorted_li)
  {'e':5, 'l':8, 'h':10}