要求:使用正则表达式希望仅获取特定字符串，即输入列表中“-”和“*”符号之间的字符串。下面是代码片段
ZTon = ['one-- and preferably only one --obvious', " Hello World", 'Now is better than never.', 'Although never is often better than *right* now.']
ZTon = [ line.strip() for line in ZTon]
print (ZTon)
r = re.compile(".^--")
portion = list(filter(r.match, ZTon)) # Read Note
print (portion)
预期响应:
['and preferably only one','right']
最佳答案
使用正则表达式
import re
ZTon = ['one-- and preferably only one --obvious', " Hello World", 'Now is better than never.', 'Although never is often better than *right* now.']
pattern=r'(--|\*)(.*)\1'
l=[]
for line in ZTon:
s=re.search(pattern,line)
if s:l.append(s.group(2).strip())
print (l)
# ['and preferably only one', 'right']
关于python - python 3 中的 List 中的特定模式字符串，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/56528228/