python - 我怎样才能让每次点击发生一次？

Question

当我将鼠标悬停在按钮上时，它会改变颜色，但我还想在单击它时将数字添加到列表中。我得到它来添加数字，但我希望每次点击只发生一次，

def button():
    mouse = pygame.mouse.get_pos()
    click = pygame.mouse.get_pressed()

    if mouse[0] < 300 and mouse[1] < 300:
        topleft.color = (255, 0, 0)
        if click[0]:
            playerpattern.append(1)
    else:
        topleft.color = (100, 0, 0)

playerpattern = []

while playing:

    print(str(playerpattern))        

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            playing = False

    button()
    win.fill((0, 0, 0))
    pygame.display.update()

pygame.quit()

如果按住单击，它只会发送垃圾邮件 1。因此，如果您单击 1 秒的时间过长，则会添加两个 1。

Answer 1

这是@TheLazyScripter 代码的一个刺探...

def button_hover():
    mouse = pygame.mouse.get_pos()

    if mouse[0] < 300 and mouse[1] < 300:
        topleft.color = (255, 0, 0)
    else:
        topleft.color = (100, 0, 0)

def clicky_button():
    mouse = pygame.mouse.get_pos()
    if mouse[0] < 300 and mouse[1] < 300:
        playerpattern.append(1)

playerpattern = []

while playing:

    print(str(playerpattern))        

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            playing = False
        if event.type == pygame.MOUSEBUTTONDOWN:
            clicky_button()

    button_hover()
    win.fill((0, 0, 0))
    pygame.display.update()

pygame.quit()

本质上，您在 for 循环中检查多种事件类型。将悬停代码与点击代码隔离开来，因为您可以悬停而不点击。当你悬停时，改变颜色。单击时，执行单击代码。