我对Python相当陌生。在一些帮助下,我编写了一些代码来从网页上抓取一些数据。但是,我只能根据代码抓取每个链接的第一页。
目前,下面的代码允许我根据第一页抓取每年数据( https://aviation-safety.net/database/dblist.php?Year=1949 )的链接。
但是,对于某些年份,特定年份的链接 ( https://aviation-safety.net/database/dblist.php?Year=1949&lang=&page=2 ) 中还有其他页面(例如第 2 页、第 3 页、第 4 页) (https://aviation-safety.net/database/dblist.php?Year=1949&lang=&page=3)
我想知道是否可以根据每年数据的附加页面检索附加链接。
#get the additional links within each Year Link
import pandas as pd
from bs4 import BeautifulSoup
import requests
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/75.0.3770.100 Safari/537.36'}
main_url = "https://aviation-safety.net/database/"
def get_and_parse_url(main_url):
result = requests.get(main_url)
soup = BeautifulSoup(result.content, 'html.parser')
data_table = [main_url + i['href'] for i in soup.select('[href*=Year]')]
return data_table
with requests.Session() as s:
data_table = get_and_parse_url(main_url)
df = pd.DataFrame(data_table, columns=['url'])
datatable2 = [] #create outside so can append to it
for anker in df.url:
result = s.get(anker, headers = headers)
soup = BeautifulSoup(result.content, 'html.parser')
datatable2.append(['https://aviation-safety.net' + i['href'] for i in soup.select('[href*="database/record"]')])
#flatten list of lists
datatable2 = [i for sublist in datatable2 for i in sublist]
df2 = pd.DataFrame(datatable2 , columns=['add_url'])
for i in df2.add_url:
print(i)
非常感谢任何形式的帮助,谢谢!
最佳答案
您可以通过收集 pagenumbers
类元素中的子 a
标记的匹配项来确定每个初始记录页面的附加页面数(仅限于顶部)一种是添加第 n 个类型);在生成实际附加页面 url 的列表理解中执行此操作;然后对这些页面使用额外的循环收集。在撰写本文时,这产生了 22,629 个不同的链接。
import requests
from bs4 import BeautifulSoup as bs
base = 'https://aviation-safety.net/database/'
headers = {'User-Agent':'Mozilla/5.0'}
inner_links = []
def get_soup(url):
r = s.get(url, headers = headers)
soup = bs(r.text, 'lxml')
return soup
with requests.Session() as s:
soup = get_soup('https://aviation-safety.net/database/')
initial_links = [base + i['href'] for i in soup.select('[href*="Year="]')]
for link in initial_links:
soup = get_soup(link)
inner_links+= ['https://aviation-safety.net' + i['href'] for i in soup.select('[href*="database/record"]')]
pages = [f'{link}&lang=&page={i.text}' for i in soup.select('.pagenumbers:nth-of-type(2) a')]
for page in pages:
soup = get_soup(page)
inner_links+= ['https://aviation-safety.net' + i['href'] for i in soup.select('[href*="database/record"]')]
关于python - 如何抓取网站主页的其他页面,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57960453/