python - 如何检查一个列表是否包含另一个列表的 2 个元素？

Question

我希望能够检查一个列表是否包含另一个列表的 2 个元素(总共有 3 个元素)

例如:

list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if #list2 contains any 2 elements of list1:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")

Answer 1

我将使用与以下问题中描述的类似的描述，只是这次检查集合交集的长度: How to find list intersection?

list1 = ["a", "b", "c"]
list2 = ["a", "f", "g", "b"]

if len(list(set(a) & set(b))) == 2:
    print("yes, list 2 contains 2 elements of list 1")
else:
    print("no, list 2 does not contain 2 elements of list 1")