是否有更好的Pythonic/面向对象方法来选择在运行时执行哪个特定类方法,具体取决于对象的类型,因为使用 type()
方法不被认为优雅(?)
我为我正在使用的三种数据类型编写了以下代码。它基本上将不同的函数存储在字典中作为值,并将其与相应的对象类型作为键配对:
import pathlib
import _io
########################################
class choose_for :
def __init__(self, var):
func_dict = {str:self.func1, pathlib.WindowsPath:self.func2, _io.TextIOWrapper:self.func3}
self.func = func_dict[type(var)]
def func1(self) :
print("Because it is for STRING like \n")
def func2(self) :
print("Because it is for PATH like \n")
def func3(self) :
print("Because it is for FILE_POINTER like \n")
def execute(self):
print("This object will be executed by : ", self.func)
self.func()
########################################
var1 = str("something")
var2 = pathlib.Path()
var3 = _io.open("file.txt")
########################################
chosen1 = choose_for(var1)
chosen1.execute()
chosen2 = choose_for(var2)
chosen2.execute()
chosen3 = choose_for(var3)
chosen3.execute()
########################################
var3.close()
它给出以下输出:
This object will be executed by : <bound method choose_for.func1 of <__main__.choose_for object at 0x0000020A150A3088>>
Because it is for STRING like
This object will be executed by : <bound method choose_for.func2 of <__main__.choose_for object at 0x0000020A1509EFC8>>
Because it is for PATH like
This object will be executed by : <bound method choose_for.func3 of <__main__.choose_for object at 0x0000020A15276B48>>
Because it is for FILE_POINTER like
对于我在这里想做的事情,还有什么技术术语吗? 我认为这可能与单分派(dispatch)、函数重载或多态性有关,但我不确定。
最佳答案
这确实是 single-dispatch ,Python 通过 functools 模块支持。无需上课。
from functools import singledispatch
@singledispatch
def execute(arg):
print(f"something with type {type(arg)}")
@execute.register(str):
def _(arg):
print("Because it is for STRING like \n")
@execute.register(pathlib.Path):
def _(arg):
print("Because it is for PATH like \n")
@execute.register(io.FileIO)
def _(arg):
print("Because it is for FILE_POINTER like \n")
测试一下,你就会发现
>>> execute("something")
Because it is for STRING like
>>> execute(pathlib.Path())
Because it is for PATH like
>>> execute(_io.open("file.txt"))
Because it is for FILE_POINTER like
>>> execute(3)
something with type <class 'int'>
要对方法使用单次调度,请使用 singledispatchmethod
,它将调度该方法的第二参数,跳过隐式提供的实例或类参数。
关于Pythonic(OO) 方式根据对象类型选择类方法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59199306/