在一组数字之后,我想在字符串中添加一个空格。例如,以下字符串应在数字后添加空格:
Before After
"0ABCD TECHNOLOGIES SERVICES" "0 ABCD TECHNOLOGIES SERVICES"
"ABCD0 TECHNOLOGIES SERVICES" "ABCD 0 TECHNOLOGIES SERVICES"
"ABCD 0TECHNOLOGIES SERVICES" "ABCD 0 TECHNOLOGIES SERVICES"
"ABCD TECHNOLOGIES0 SERVICES" "ABCD TECHNOLOGIES 0 SERVICES"
"ABCD TECHNOLOGIES 0SERVICES" "ABCD TECHNOLOGIES 0 SERVICES"
"ABCD TECHNOLOGIES SERVICES0" "ABCD TECHNOLOGIES SERVICES 0"
我一直在尝试使用 Python 中的正则表达式,如下所示:
text= re.sub(r'([0-9]+)?([A-Za-z]+)?([0-9]+)?',
r'\1 \2 \3',
text,
0,
re.IGNORECASE)
使用前面的代码,我得到了不想要的空格,这会影响其他正则表达式转换:
"0 abcd technologies services "
如何在字符串中添加空格而不添加不需要的空格?
最佳答案
您可以使用
re.sub(r'(?<=\d)(?=[^\d\s])|(?<=[^\d\s])(?=\d)', ' ', text)
请参阅regex demo .
图案详细信息
-
(?<=\d)(?=[^\d\s])
- 数字和字符之间的位置(数字和空格除外) -
|
- 或 -
(?<=[^\d\s])(?=\d)
- 数字以外的字符与空格和数字之间的位置。
import re
tests = ['0ABCD TECHNOLOGIES SERVICES',
'ABCD0 TECHNOLOGIES SERVICES',
'ABCD 0TECHNOLOGIES SERVICES',
'ABCD TECHNOLOGIES0 SERVICES',
'ABCD TECHNOLOGIES 0SERVICES',
'ABCD TECHNOLOGIES SERVICES0']
rx = re.compile(r'(?<=\d)(?=[^\d\s])|(?<=[^\d\s])(?=\d)')
for test in tests:
print(rx.sub(' ', test))
输出:
0 ABCD TECHNOLOGIES SERVICES
ABCD 0 TECHNOLOGIES SERVICES
ABCD 0 TECHNOLOGIES SERVICES
ABCD TECHNOLOGIES 0 SERVICES
ABCD TECHNOLOGIES 0 SERVICES
ABCD TECHNOLOGIES SERVICES 0
关于python - 正则表达式:在数字后跟字母时添加空格,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59724564/