python - django动态 zipper 内部服务器错误

Question

我已启用调试，但没有显示任何内容。我看到的只是“500 内部服务器错误。 我在这个脚本中做错了什么？

python

import zipfile
from zipfile import ZipFile
import cStringIO as StringIO
from django.http import HttpResponse
from django.core.servers.basehttp import FileWrapper

def zipit (request):
  files = ['/home/dbs/public_html/download/codex/video.html', '/home/dbs/public_html/download/audio/audio.html']
  buffer= StringIO.StringIO()
  z= zipfile.ZipFile( buffer, "w" )
  [z.write(f) for f in files]
  z.close()
  response = HttpResponse(FileWrapper(z), content_type='application/zip')
  response['Content-Disposition'] = 'attachment; filename=z.zip'
  return HttpResponse(response, mimetype="application/x-zip-compressed")

Answer 1

试试这个:

import zipfile
from zipfile import ZipFile
import cStringIO as StringIO
from django.http import HttpResponse
from django.core.servers.basehttp import FileWrapper
import os

def zipit (request):
    files = ['/home/dbs/public_html/download/codex/video.html', '/home/dbs/public_html/download/audio/audio.html']
    buffer = StringIO.StringIO()
    z = zipfile.ZipFile(buffer, "w")
    [z.write(f, os.path.join('codex', os.path.basename(f))) for f in files]
    z.close()
    buffer.seek(0)
    response = HttpResponse(buffer.read())
    response['Content-Disposition'] = 'attachment; filename=z.zip'
    response['Content-Type'] = 'application/x-zip'
    return response

但请尽量不要让 django 返回二进制文件，它从来没有为此设计，你的 http 服务器应该处理它。