更新1: 进行以下更正后:
from PyQt4 import QtGui, QtCore
class LoginWidget(QtGui.QWidget):
success = QtCore.pyqtSignal() # Might be QtCore.pyqtSignal
def __init__(self, parent=None):
super(LoginWidget, self).__init__(parent)
self.Username = QtGui.QLineEdit(self)
self.Password = QtGui.QLineEdit(self)
self.buttonLogin = QtGui.QPushButton('Login', self)
self.buttonLogin.clicked.connect(self.handleLogin)
loginLayout = QtGui.QFormLayout()
loginLayout.addRow("Username", self.Username)
loginLayout.addRow("Password", self.Password)
layout = QtGui.QVBoxLayout(self)
layout.addLayout(loginLayout)
layout.addWidget(self.Username)
layout.addWidget(self.Password)
layout.addWidget(self.buttonLogin)
def handleLogin(self):
if (self.Username.text() == 'example' and
self.Password.text() == 'example'):
self.success.emit()
# OR you know that the main window is the parent of this class
# so you could call self.parent().P_3()
# Signals are better though
else:
QtGui.QMessageBox.warning(
self, 'Error', 'Incorrect Username/Password combination!')
class Page3(QtGui.QWidget):
def __init__(self, parent=None):
super(Page3, self).__init__(parent)
layout = QtGui.QHBoxLayout()
self.Hello = QtGui.QLabel('Hello')
layout.addWidget(self.Hello)
self.setLayout(layout)
class page1(QtGui.QWidget):
def __init__(self, parent=None):
super(page1, self).__init__(parent)
layout = QtGui.QHBoxLayout()
self.nextpage = QtGui.QPushButton('Page2')
layout.addWidget(self.nextpage)
self.setLayout(layout)
class MainWindow(QtGui.QMainWindow):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
self.central_widget = QtGui.QStackedWidget()
self.setCentralWidget(self.central_widget)
Page1 = page1(self)
Page1.nextpage.clicked.connect(self.P_2)
self.central_widget.addWidget(Page1)
def P_2(self):
page2 = LoginWidget(self)
# Connect your signal to a method. When success is emitted it will call P_3()
page2.success.connect(self.P_3) # Note: P_3 does not have "()" with it
self.central_widget.addWidget(page2)
self.central_widget.setCurrentWidget(page2)
def P_3(self):
print("yay")
page3 = Page3(self)
# self.central_widget.addWidget(Page3) # you are calling the class (lowercase)
# self.central_widget.setCurrentWidget(Page3) # calling the class (lowercase)
self.central_widget.addWidget(Page3)
self.central_widget.setCurrentWidget(Page3)
if __name__ == '__main__':
User = ''
app = QtGui.QApplication([])
window = MainWindow()
window.showFullScreen()
app.exec_()
我收到此错误:
回溯(最近一次调用最后一次): 文件“C:\Users\Hamzah\My Documents\Work\A-Level\USB Stuff\Pie Chart 2.py”，第 66 行，位于 P_3 self.central_widget.addWidget(第3页) TypeError: QStackedWidget.addWidget(QWidget): 参数 1 具有意外类型 'PyQt4.QtCore.pyqtWrapperType
问题:
下面的代码显示了在页面 1、登录页面(页面 2)和页面 3 之间切换布局的示例。但是，我似乎无法将布局从页面 2 切换到页面 3。我可以将布局从页面 1 切换到第2页？!顺便说一下，运行程序时(如果您正在运行它)，登录详细信息是“example”和“example”，或者查看代码以获取详细信息:
from PyQt4 import QtCore, QtGui
class MainWindow(QtGui.QMainWindow):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
self.central_widget = QtGui.QStackedWidget()
self.setCentralWidget(self.central_widget)
Page1 = page1(self)
Page1.nextpage.clicked.connect(self.P_2)
self.central_widget.addWidget(Page1)
def P_2(self):
page2 = LoginWidget(self)
self.central_widget.addWidget(page2)
self.central_widget.setCurrentWidget(page2)
def P_3(self):
print("Why won't the page open!!!???")
page3 = Page3(self)
self.central_widget.addWidget(Page3)
self.central_widget.setCurrentWidget(Page3)
class LoginWidget(QtGui.QWidget):
def __init__(self, parent=None):
super(LoginWidget, self).__init__(parent)
self.Username = QtGui.QLineEdit(self)
self.Password = QtGui.QLineEdit(self)
self.buttonLogin = QtGui.QPushButton('Login', self)
self.buttonLogin.clicked.connect(self.handleLogin)
loginLayout = QtGui.QFormLayout()
loginLayout.addRow("Username", self.Username)
loginLayout.addRow("Password", self.Password)
layout = QtGui.QVBoxLayout(self)
layout.addLayout(loginLayout)
layout.addWidget(self.Username)
layout.addWidget(self.Password)
layout.addWidget(self.buttonLogin)
def handleLogin(self):
if (self.Username.text() == 'example' and
self.Password.text() == 'example'):
MainWindow().P_3()
else:
QtGui.QMessageBox.warning(
self, 'Error', 'Incorrect Username/Password combination!')
class page1(QtGui.QWidget):
def __init__(self, parent=None):
super(page1, self).__init__(parent)
layout = QtGui.QHBoxLayout()
self.nextpage = QtGui.QPushButton('Page2')
layout.addWidget(self.nextpage)
self.setLayout(layout)
class Page3(QtGui.QWidget):
def __init__(self, parent=None):
super(Page3, self).__init__(parent)
layout = QtGui.QHBoxLayout()
self.Hello = QtGui.QLabel('Hello')
layout.addWidget(self.Hello)
self.setLayout(layout)
if __name__ == '__main__':
User = ''
app = QtGui.QApplication([])
window = MainWindow()
window.showFullScreen()
app.exec_()
最佳答案
问题出在您的 LoginWidget 中。 handleLogin 正在创建一个新的 MainWinow 并尝试调用第 3 页。
您不想创建新的主窗口，并且您不需要登录所需的主窗口实例。
我建议使用信号
class LoginWidget(QtGui.QWidget):
success = QtCore.Signal() # Might be QtCore.pyqtSignal
...
def handleLogin(self):
if (self.Username.text() == 'example' and
self.Password.text() == 'example'):
self.success.emit()
# OR you know that the main window is the parent of this class
# so you could call self.parent().P_3()
# Signals are better though
else:
QtGui.QMessageBox.warning(
self, 'Error', 'Incorrect Username/Password combination!')
class MainWindow(QtGui.QMainWindow):
def P_2(self):
page2 = LoginWidget(self)
# Connect your signal to a method. When success is emitted it will call P_3()
page2.success.connect(self.P_3) # Note: P_3 does not have "()" with it
self.central_widget.addWidget(page2)
self.central_widget.setCurrentWidget(page2)
如果您需要涉及信号的参数，请使用 lambda 函数。
page2.success.connect(lambda arg="": method(arg))
另请注意 P_3 中的错误
def P_3(self):
page3 = Page3(self)
# self.central_widget.addWidget(Page3) # you are calling the class (lowercase)
# self.central_widget.setCurrentWidget(Page3) # calling the class (lowercase)
self.central_widget.addWidget(page3)
self.central_widget.setCurrentWidget(page3)
关于python - 如何在 PyQt/Python 中切换布局？ (先进的)，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/22819268/