我对编程还很陌生，而且只接触了一个月。目前我正在尝试获取用户输入，将其存储在列表中，然后将该列表传递到函数中。我在使用列表作为函数的参数(最后一行代码)时遇到问题。提前致谢!
grade_list = []
percentages = 0
while True:
percentages = input("Enter some numbers here: ")
if percentages == "done":
break
grade_list.append(percentages)
print(grade_list)
def gpaCalc(marks):
gpaList = []
for grade in marks: #sorts data
if grade <= 49.99:
grade = 0.00
elif 50 <= grade <= 52.99:
grade = 0.70
elif 53 <= grade <= 56.99:
grade = 1.00
elif 57 <= grade <= 59.99:
grade = 1.30
elif 60 <= grade <= 62.99:
grade = 1.70
elif 63 <= grade <= 66.99:
grade = 2.00
elif 67 <= grade <= 69.99:
grade = 2.30
elif 70 <= grade <= 72.99:
grade = 2.70
elif 73 <= grade <= 76.99:
grade = 3.00
elif 77 <= grade <= 79.99:
grade = 3.30
elif 80 <= grade <= 84.99:
grade = 3.70
elif 85 <= grade <= 89.99:
grade = 3.90
elif 90 <= grade <= 100:
grade = 4.00
gpaList.append(grade) #gathers data into list
gpaList.sort()
return gpaList
print (gpaCalc(PROBLEM))
最佳答案
您可以像通常将列表传递到任何函数中一样传递列表，只需始终确保通过正确索引访问列表中的项目，而不是计算整个列表。请改用以下内容:
def gpaCalc(marks):
gpaList = []
for grade in marks[0]: #sorts data
if grade <= 49.99:
grade = 0.00
elif 50 <= grade <= 52.99:
grade = 0.70
elif 53 <= grade <= 56.99:
grade = 1.00
elif 57 <= grade <= 59.99:
grade = 1.30
elif 60 <= grade <= 62.99:
grade = 1.70
elif 63 <= grade <= 66.99:
grade = 2.00
elif 67 <= grade <= 69.99:
grade = 2.30
elif 70 <= grade <= 72.99:
grade = 2.70
elif 73 <= grade <= 76.99:
grade = 3.00
elif 77 <= grade <= 79.99:
grade = 3.30
elif 80 <= grade <= 84.99:
grade = 3.70
elif 85 <= grade <= 89.99:
grade = 3.90
elif 90 <= grade <= 100:
grade = 4.00
gpaList.append(grade) #gathers data into list
gpaList.sort()
return gpaList
grade_list = []
percentages = 0
while True:
percentages = input("Enter some numbers here: ")
if percentages == "done":
break
grade_list.append(percentages)
print(gpaCalc(grade_list))
关于python - 如何使用 python 在函数中使用列表作为参数，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/32419623/