我尝试根据 query_params 在 View 集上使用不同的分页类集。
class BlockViewSet(viewsets.ModelViewSet):
pagination_class = defaultPaginationClass
def get_queryset(self):
queryset = Block.objects.all()
user = self.request.query_params.get('user', None)
if user is no None:
queryset = queryset.filter(user=user)
return queryset
因此,如果向 /block/
发出 get 请求,我想使用 defaultPagination 类,而如果向 /block/?user=1
发出请求,我想使用 customPagination 类。
最佳答案
尝试重新定义 paginator
属性,如果有用户查询参数,请将自定义分页类分配给 self._paginator
@property
def paginator(self):
"""
The paginator instance associated with the view, or `None`.
"""
if not hasattr(self, '_paginator'):
if self.pagination_class is None:
self._paginator = None
else:
user = self.request.query_params.get('user', None)
if user is not None:
self._paginator = customPaginationClass()
else:
self._paginator = self.pagination_class()
return self._paginator
决赛
class BlockViewSet(viewsets.ModelViewSet):
pagination_class = defaultPaginationClass
@property
def paginator(self):
"""
The paginator instance associated with the view, or `None`.
"""
if not hasattr(self, '_paginator'):
if self.pagination_class is None:
self._paginator = None
else:
user = self.request.query_params.get('user', None)
if user is not None:
self._paginator = customPaginationClass()
else:
self._paginator = self.pagination_class()
return self._paginator
def get_queryset(self):
queryset = Block.objects.all()
user = self.request.query_params.get('user', None)
if user is no None:
queryset = queryset.filter(user=user)
return queryset
关于python - Django Rest Framework (DRF) 如何根据 query_params 设置分页类?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38988272/