python - 如何绘制如下所示的 'x' 形状

Question

我是Python新手，请有人帮忙画一个如下所示的形状。该程序必须将星星的数量作为输入。

星星数量 = 7

*      *
**    **
***  *** 
********
***  *** 
**    **
*      *

我的代码:

count = int(input('star count : '))
pattern_size = count + 1
for t in range(1, pattern_size):
    pattern = list(" " * pattern_size)
    pattern[:t] = "*" * t
    pattern[-t:] = '*' * t
    print(''.join(pattern))

star count :  9
*        *
**      **
***    ***
****  ****
**********
**********
**********
**********
**********

Answer 1

这是一个易于理解的示例，在您的方法中使用了两个 for 循环:一个只是另一个的逆

count = int(input('star count : '))
pattern_size = count + 1
for t in range(1, int(pattern_size/2)):
    pattern = list(" " * pattern_size)
    pattern[:t] = "*" * t
    pattern[-t:] = '*' * t
    print(''.join(pattern))

for t in range(int(pattern_size/2), 0, -1):
    pattern = list(" " * pattern_size)
    pattern[:t] = "*" * t
    pattern[-t:] = '*' * t
    print(''.join(pattern))

更高级的方法是使用字符串方法.center()，如下所示:

count = int(input('star count : '))
pattern_size = count + 1
for t in range(1, int(pattern_size/2)):
    print((" " * (pattern_size-t*2)).center(pattern_size, '*'))
for t in range(int(pattern_size/2), 0, -1):
    print((" " * (pattern_size - t * 2)).center(pattern_size, '*'))