我有一个 dicts
列表,其中我需要合并包含相同 ID
键/值的多个字典。我目前所做的不起作用,它只输出一个新的字典,其格式正确,但我需要一个新列表中的所有合并字典(或就地突变,我不太关心这一点) )。
列表中并没有真正规定其中可能存在的具有相同 ID 的字典数量的最小值或最大值,它是另一个变化函数的输出。
这就是我所拥有的
字典列表:
# actual ID's are longer and alphanumeric, this is for simplicity.
# dicts with same ID will also have the same 'taskConstraint',
# but that is a side effect and can't be used as a filter
test_update_list = [
{"ID":"1","taskConstraint": "FIXT","plannedCompletionDate":"2017-07-29","constraintDate":"2017-07-29"},
{"ID":"1","taskConstraint": "FIXT","plannedStartDate":"2017-07-25","constraintDate":"2017-07-25"},
{"ID":"2","taskConstraint": "MSO","plannedCompletionDate":"2017-07-29","constraintDate":"2017-07-29"},
{"ID":"1","taskConstraint": "FIXT","noteText": "Note update text"},
{"ID":"2","taskConstraint": "MSO","noteText": "Note update text"},
{"ID":"3","taskConstraint": "MFO","noteText": "Note update text"},
{"ID":"3","taskConstraint": "MFO","plannedStartDate":"2017-07-25","constraintDate":"2017-07-25"}]
所需输出:
desired_output = [
{"ID":"1","taskConstraint":"FIXT","plannedStartDate":"2017-07-25","constraintDate":"2017-07-25","plannedCompletionDate":"2017-07-29"},
{"ID":"2","taskConstraint": "MSO","plannedCompletionDate":"2017-07-29","constraintDate":"2017-07-29","noteText": "Note update text"},
{"ID":"3","taskConstraint": "MFO","plannedStartDate":"2017-07-25","constraintDate":"2017-07-25","noteText": "Note update text"}]
到目前为止我的糟糕且不正确的尝试:
test_update_list = [
{"ID":"1","taskConstraint": "FIXT","plannedCompletionDate":"2017-07-29","constraintDate":"2017-07-29"},
{"ID":"1","taskConstraint": "FIXT","plannedStartDate":"2017-07-25","constraintDate":"2017-07-25"},
{"ID":"2","taskConstraint": "MSO","plannedCompletionDate":"2017-07-29","constraintDate":"2017-07-29"},
{"ID":"1","taskConstraint": "FIXT","noteText": "Note update text"},
{"ID":"2","taskConstraint": "MSO","noteText": "Note update text"},
{"ID":"3","taskConstraint": "MFO","noteText": "Note update text"},
{"ID":"3","taskConstraint": "MFO","plannedStartDate":"2017-07-25","constraintDate":"2017-07-25"}]
new_update_list = []
for task in test_update_list:
if len(new_update_list) > 0 and task not in new_update_list:
for new_task in new_update_list:
if task['ID'] == new_task['ID']:
new_task = { **task, **new_task }
else:
new_update_list.append(task)
打印(new_update_list)
输出...
[{'ID': '1', 'plannedCompletionDate': '2017-07-29', 'constraintDate': '2017-07-29', 'taskConstraint': 'FIXT'}]
最佳答案
您可以将新数据添加到 dict
而不是 list
,其中键为 ID。要获取预期的字典列表,请稍后在字典上调用 .values()
。
>>> d = {}
>>> for dct in test_update_list:
... d.setdefault(dct['ID'], {}).update(dct)
...
>>> pprint(list(d.values()))
[{'ID': '1',
'constraintDate': '2017-07-25',
'noteText': 'Note update text',
'plannedCompletionDate': '2017-07-29',
'plannedStartDate': '2017-07-25',
'taskConstraint': 'FIXT'},
{'ID': '2',
'constraintDate': '2017-07-29',
'noteText': 'Note update text',
'plannedCompletionDate': '2017-07-29',
'taskConstraint': 'MSO'},
{'ID': '3',
'constraintDate': '2017-07-25',
'noteText': 'Note update text',
'plannedStartDate': '2017-07-25',
'taskConstraint': 'MFO'}]
关于python - 循环字典列表并合并具有相同ID的字典,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45351503/