当我执行下面的程序时
import MySQLdb
cn = MySQLdb.connect(host="localhost", user="root", passwd="mysqlroot",
db="sv_data")
cursor = cn.cursor()
cursor.execute("select addressline1, zipcode from sv_address where zipcode = '10011'")
for (addressline1, zipcode) in cursor:
print(addressline1, zipcode)
cursor.close()
cn.close()
效果很好。但是,当我尝试在查询中添加参数时,如下所示
import MySQLdb
cn = MySQLdb.connect(host="localhost", user="root", passwd="****",
db="sv_data")
cursor = cn.cursor()
a="10011"
cursor.execute("select addressline1, zipcode from sv_address where zipcode =
%s", (a))
for (addressline1, zipcode) in cursor:
print(addressline1, zipcode)
cursor.close()
cn.close()
出现错误ProgrammingError:在字符串格式化过程中并非所有参数都被转换
您能告诉我如何解决这个问题吗?我尝试了各种选择。 zipcode 是 mysqldb 中的 varchar 字段
最佳答案
您没有传递参数。你宁愿给它一个字符串。
试试这个。
cursor.execute("select addressline1, zipcode from sv_address where zipcode = %s" % a )
最好的方法是将参数和 sql_query
分开
_sql = "select addressline1, zipcode from sv_address where zipcode = {0}"
cursor.execute(_sql.format(a))
关于python - 如何解决Python错误 "not all arguments converted while string formatting",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45647026/