1st Text file format .
cake,60
cake,30
tart,50
bread,89
2nd Text file format .
cake,10
cake,10
tart,10
bread,10
我尝试过的代码。
from collections import defaultdict
answer = defaultdict(int)
recordNum = int(input("Which txt files do you want to read from "))
count = 1
counter = 0
counst = 1
countesr = 0
while recordNum > counter:
with open('txt'+str(count)+'.txt', 'r') as f:
for line in f:
k, v = line.strip().split(',')
answer[k.strip()] += int(v.strip())
count = count+1
counter = counter+1
print(answer)
问题。
I want the dictionary to be {'cake': '100', 'tart': '60', 'bread': '99'}
but it prints like this {'cake': '30', 'tart': '50', 'bread': '89'}
“蛋糕”值不是与 txt 文件一和二中的其他蛋糕值相加,而是被替换为最新值。我该如何解决这个问题。
最佳答案
您可以使用collections.defaultdict
累积计数:
from collections import defaultdict
answer = defaultdict(int)
with open("file.txt", 'r') as f:
for line in f:
k, v = line.split(',')
answer[k.strip()] += int(v.strip())
# turn values back to string
for k in answer:
answer[k] = str(answer[k])
print(answer)
如果计数均为正数,您可以考虑使用collections.Counter
。
关于python - 如何添加键值而不是替换它们。 Python 字典,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45797365/