我正在用 Pygame 编写一个小游戏,但我不知道如何获得鼠标点击。我已经弄清楚了一些,但说实话,我并没有度过最好的时光。
这是我所拥有的:
import pygame
pygame.init()
def menu():
title_font = pygame.font.SysFont("monospace",64)
button_font = pygame.font.SysFont("monospace", 30)
screen_size = (1280,950)
screen = pygame.display.set_mode(screen_size)
background = (255,255,255)
screen.fill(background)
play_button = pygame.Rect(250,600,200,100)
quit_button = pygame.Rect(850,600,200,100)
controls_button = pygame.Rect(550,600,200,100)
pygame.draw.rect(screen, (0,255,0), play_button)
pygame.draw.rect(screen, (255,0,0), quit_button)
pygame.draw.rect(screen, (255,229,0), controls_button)
title = title_font.render("Fightastic!", 1, (0,0,0))
screen.blit(title, (450,300))
play_text = button_font.render("START",1,(0,0,0))
screen.blit(play_text, (310,635))
quit_text = button_font.render("QUIT",1,(0,0,0))
screen.blit(quit_text, (910,635))
controls_text = button_font.render("CONTROLS",1,(0,0,0))
screen.blit(controls_text, (580,635))
buttons = [play_button, quit_button, controls_button]
while True:
events = pygame.event.get()
for event in events:
if event.type == pygame.QUIT:
exit()
mouse_cursor = pygame.mouse.get_pos()
mouse_pressed = pygame.mouse.get_pressed()
option = 0
for i in range(len(buttons)):
if buttons[i].collidepoint( mouse_cursor):
option = i+1
if option == 1:
print ("YO I GOT CLICKED")
elif option == 2:
print ("CLICKED MY DUDE")
elif option == 3:
quit()
pygame.display.update()
menu()
游戏的菜单是唯一需要点击的部分,所以这就是我所展示的全部内容。
谢谢!
最佳答案
您已经有了pygame.mouse.get_pressed()
,因此可以使用它来检查单击了哪个按钮。
option = 0
if mouse_pressed[0]: # check if left button was clicked
for i, but in enumerate(buttons, 1): # get button and its number
if but.collidepoint(mouse_cursor): # check collision
option = i # remember button number
break # no need to check other buttons
但是使用 pygame.mouse.get_pressed()
会产生一个问题 - 当你按住鼠标按钮时,它会返回 True
(所以看起来每次点击都会有很多次点击)第二)所以如果您更改屏幕上的按钮并且新按钮将位于同一位置,那么它将自动单击新按钮。最好使用 event.type == pygame.MOUSEBUTTONDOWN
它只创建一次点击。
while True:
option = 0
for event in pygame.event.get():
if event.type == pygame.QUIT:
exit()
if event.type == pygame.MOUSEBUTTONDOWN:
for i, but in enumerate(buttons, 1):
if but.collidepoint(event.pos):
option = i
break # no need to check other buttons
if option == 1:
print ("YO I GOT CLICKED")
elif option == 2:
print ("CLICKED MY DUDE")
elif option == 3:
quit()
pygame.display.update()
<小时/>
顺便说一句:
您可以保留带有回调的按钮(不带 ()
的函数名称)
buttons = [
(play_button, play_function),
(controls_button, control_function),
(quit_button, quit_function),
]
然后你可以直接调用函数/回调(使用()
)而不使用选项
if event.type == pygame.MOUSEBUTTONDOWN:
for rect, callback in buttons:
if rect.collidepoint(event.pos):
callback() # execute function
break # no need to check other buttons
完整的工作代码
import pygame
# --- constants --- (UPPER_CASE_NAMES)
SCREEN_WIDTH = 1280
SCREEN_HEIGHT = 950
WHITE = (255, 255, 255)
# --- functions --- (lower_case_names)
def play_function():
print("YO I GOT CLICKED")
def controls_function():
print("CLICKED MY DUDE")
def quit_function():
pygame.quit()
quit()
def menu(screen):
# - init -
title_font = pygame.font.SysFont("monospace", 64)
button_font = pygame.font.SysFont("monospace", 30)
# - objects -
play_button = pygame.Rect(250,600,200,100)
quit_button = pygame.Rect(850,600,200,100)
controls_button = pygame.Rect(550,600,200,100)
buttons = [
(play_button, play_function),
(controls_button, controls_function),
(quit_button, quit_function),
]
# - draws -
screen.fill(WHITE)
title = title_font.render("Fightastic!", 1, (0,0,0))
screen.blit(title, (450,300))
pygame.draw.rect(screen, (0,255,0), play_button)
play_text = button_font.render("START",1,(0,0,0))
screen.blit(play_text, (310,635))
pygame.draw.rect(screen, (255,0,0), quit_button)
quit_text = button_font.render("QUIT",1,(0,0,0))
screen.blit(quit_text, (910,635))
pygame.draw.rect(screen, (255,229,0), controls_button)
controls_text = button_font.render("CONTROLS",1,(0,0,0))
screen.blit(controls_text, (580,635))
pygame.display.update()
# - mainloop -
clock = pygame.time.Clock()
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
exit()
if event.type == pygame.MOUSEBUTTONDOWN:
for rect, callback in buttons:
if rect.collidepoint(event.pos):
callback() # execute function
break # no need to check other buttons
clock.tick(5) # 5 FPS - to slow down game and use less CPU
# --- main ---
pygame.init()
screen = pygame.display.set_mode((SCREEN_WIDTH, SCREEN_HEIGHT))
menu(screen)
关于python - 如何获得鼠标点击次数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48157024/