这是我正在编写的代码
import csv
import openpyxl
def read_file(fn):
rows = []
with open(fn) as f:
reader = csv.reader(f, quotechar='"',delimiter=",")
for row in reader:
if row:
rows.append(row)
return rows
replace = {x[0]:x[1:] for x in read_file("replace.csv")}
delete = set( (row[0] for row in read_file("delete.csv")) )
result = []
input_file="input.csv"
with open(input_file) as f:
reader = csv.reader(f, quotechar='"')
for row in reader:
if row:
if row[7] in delete:
continue
elif row[7] in replace:
result.append(replace[row[7]])
else:
result.append(row)
with open ("done.csv", "w+", newline="") as f:
w = csv.writer(f,quotechar='"', delimiter= ",")
w.writerows(result)
这是我的文件:
输入.csv:
c1,c2,c3,c4,c5,c6,c7,c8,c9,c10,c11,c12,c13
"-","-","-","-","-","-","-","aaaaa","-","-","bbbbb","-",","
"-","-","-","-","-","-","-","ccccc","-","-","ddddd","-",","
"-","-","-","-","-","-","-","eeeee","-","-","fffff","-",","
这是一个 13 列的 csv。我只对第 8 和 11 字段感兴趣。
这是我的replace.csv:
"aaaaa","11111","22222"
删除.csv:
ccccc
所以我正在做的是将replace.csv的第一列(逐行)与input.csv的第8列进行比较,如果它们匹配,则将input.csv的第8列替换为replace.csv的第二列输入的第 11 列与 Replace.csv 的第 3 列 对于delete.csv,它会逐行比较两个文件,如果发现匹配,则会删除整行。 如果replace.csv 或delete.csv 中不存在任何行,则按原样打印该行。 所以我想要的输出是:
c1,c2,c3,c4,c5,c6,c7,c8,c9,c10,c11,c12,c13
"-","-","-","-","-","-","-",11111,"-","-",22222,"-",","
"-","-","-","-","-","-","-","eeeee","-","-","fffff","-",","
但是当我运行这段代码时,它会给出如下输出:
c1,c2,c3,c4,c5,c6,c7,c8,c9,c10,c11,c12,c13
11111,22222
我哪里出错了? 我正在尝试更改我之前发布的问题的程序。由于输入文件已更改,我正在尝试更改我的程序。 https://stackoverflow.com/a/54388144/9279313
最佳答案
@anuj 我认为 SafeDev 的解决方案是最佳的,但如果您不想使用 pandas,只需对代码进行少量更改即可。
for row in reader:
if row:
if row[7] in delete:
continue
elif row[7] in replace:
key = row[7]
row[7] = replace[key][0]
row[10]= replace[key][1]
result.append(row)
else:
result.append(row)
希望这能解决您的问题。
关于python - 使用 python 替换和删除 csv 中的列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54454290/