Python OOP对象打印属性问题

Question

所以我正在开发一个纸牌游戏，当我尝试形成一个 Pile 类时，我构造了一个函数来打印纸牌类中的纸牌以及纸牌类中的纸牌列表。当我尝试在堆类中使用卡类(在其他类中工作)中的函数时，我没有得到预期的结果。我该如何解决这个问题？

卡片类别:

import random
from Enums import *

class Card:
    def __init__(self):
        self.suit = Suit.find(random.randint(1, 4))
        self.rank = Rank.find(random.randint(1, 14))

    def show(self):
        print (self.rank.value[1], "of", self.suit.value[1])

桩类:

from Enums import *
from Card import *
from Hand import *

class Pile:
    def __init__(self):
        self.cards = []
        self.cards.append(Card())

    def discard(self, hand, card):
        self.cards.append(card)

        if (not searchCard(self, hand, card)):
            print ("The card was not found, please select another one or cheat")
            return True
        else:
            return False

    def takePile(self, hand):
        for x in self.cards:
            hand.cards.append(self.cards[x])

    def clearPile(self):
        while len(self.cards) > 0:
            self.cards.pop()

    def searchCard(self, hand, card):
        flag = False

        for x in hand.cards and not flag:
            if (hand.cards[x].rank.value[0] == card.rank.value[0]):
                if (hand.cards[x].suit.value[0] == card.suit.value[0]):
                    hand.cards[x].pop()
                    flag = True

        return flag

    def showCurrent(self):
        for x in self.cards:
            x.show()

我指的是Card类中的show函数以及Pile类中的showCurrent和init

当我运行游戏和线路时

print ("It's your turn now, the pile presents a", pile.showCurrent())

我从 Card 类中的 show 函数中得到 None 而不是打印，如下所示:

现在轮到你了，堆里呈现的是 None

Answer 1

主要问题是您正在打印 showCurrent() 的结果，即None 。要解决此问题，只需将调用移至 showCurrent出print :

print("It's your turn now, the pile presents a")
pile.showCurrent()

此外，您可能想更改 show正确的方法__str__方法，使其更加通用。您必须更改您的 showCurrent方法也是:

# in class Card:
def __str__(self): # just return the formatted string here
    return "%s of %s" % (self.rank.value[1], self.suit.value[1])

# in class Pile:
def showCurrent(self): # print the string here
    for x in self.cards:
        print(x) # this calls str(x), which calls x.__str__()

但是您的消息表明您实际上只想打印最上面的卡片，而不是整个堆栈。与__str__您现在可以直接在 print 中执行此操作调用:

print("It's your turn now, the pile presents a", pile.cards[0]) # calls __str__