Python将数组打印成两个结果

Question

我无法打印出第二行

我尝试使用除以2并使用两个for循环来打印它，

A=[1,2,3,4,5,6,7,8]
w=len(A)
T=w/2
for i in range(T):
  for ii in range(T):
    print A[ii]


A=[1,2,3,4,5,6,7,8]

我想打印 [1,2,3,4] 和 [5,6,7,8]

Answer 1

使用slicing :

A=[1,2,3,4,5,6,7,8]

print(A[:len(A)//2])                # print(A[:4])
print(A[len(A)//2:])                # print(A[4:])

输出:

[1, 2, 3, 4]
[5, 6, 7, 8]

编辑:

为了理解；

A=[1,2,3,4,5,6,7,8]
w = len(A)

first_part = []
sec_part = []
count = 0                  # counter var to check for the first/sec half of list
for i in range((w)):
     if count < w//2:
          count += 1
          first_part.append(A[i])
     else:
      sec_part.append(A[i])

print(first_part)
print(sec_part)

输出:

[1, 2, 3, 4]
[5, 6, 7, 8]