c - 名称无法显示

Question

问题:当输入*和#时，用户需要重新输入名称。最大输入限制为 25 个字符，并以 enter 键结束输入。

#include <stdio.h>
#include <conio.h>
#define MAX 25
char welcomeMsg[]= "Please enter your name without '*' or # " ;
char errorMsg[]= "\nError, please re-type your name. ";

void main(void)
{
int j;
char input;
char name[MAX];
j=0;
puts(welcomeMsg);

do
{
    input = getche();
    if(input == '*' || input =='#' )
    {
        puts(errorMsg);
        j = 0;
        continue;
    }
    scanf("%s", name[j]);
    j++;
} while ( j < MAX && input != '\r' );

name[j] = NULL;
puts("\nYour name is");
puts(name);
}

Answer 1

我修改了你的代码。请参阅下面的片段代码

#include <stdio.h>
#include <conio.h>
#define MAX 25
char welcomeMsg[]= "Please enter your name without '*' or # " ;
char errorMsg[]= "\nError, please re-type your name. ";

void main(void)
{
    int j;
    char input;
    char name[MAX];
    j=0;
    puts(welcomeMsg);

    do
    {
        input = getche();
        if(input == '*' || input =='#' )
        {
            puts(errorMsg);
            j = 0;
            continue;
        }
        name[j] = input;
        j++;
    } while ( j < MAX && input != '\r' );

    name[j] = 0;
    puts("\nYour name is");
    puts(name);
}