c - 再次自动运行 C 代码

Question

如果最初输入的值小于 0 或大于 23，我希望用户能够立即重新输入另一个值。目前，我的代码输出“请重新输入小于 24 的值”并停止。然后必须再次运行它，然后用户才能重新输入另一个值。

{
    printf ("What is the height of the half-pyramids?\n");
        int height = get_int();
        if (height>23)
        {
            printf("please re-enter a value less than 24\n");
        }
        else if (height<0)
        {
            printf("please re-enter a value more than 0\n");
        }
        else
        {
            printf("%i", height);
    }

}

Answer 1

使用循环。

while(1) {
    printf ("What is the height of the half-pyramids?\n");
    int height = get_int();
    if (height>23)
    {
        printf("please re-enter a value less than 24\n");
    }
    else if (height<0)
    {
        printf("please re-enter a value more than 0\n");
    }
    else
    {
        printf("%d\n", height);
        break; // stop stop looping
}

顺便说一句，使用 %d 打印整数更为惯用，而不是 %i。请参阅What is the difference between conversion specifiers %i and %d in formatted IO functions (*printf / *scanf)