你好,我正在学习指针,所以我创建了一个计算器。 我设法从函数返回值和指针,但通过全局声明它们。我如何在本地声明它们?
#include <stdio.h>
#include <stdlib.h>
所有函数的声明
int Addition();
int Subtraction();
int Devision();
int Multiplication();
全局变量的声明,我想在本地声明它们
int p;
int n;
int *r=&n;
int *b=&p;
主函数开始
int main()
{
int g,s;
while (1)
{
printf("Please choose the Arithmetic operation: \n");
printf("Addition-> 1 \nSubtraction-> 2 \nDevision-> 3 \nMultiplication-> 4 \nExit-> 0\n ");
scanf("%d",&g);
用户通过输入一个数字(1、2、3、4或0退出)来选择算术运算(函数)
if (g==1)
{
s=Addition(r,b);
printf("The addition result is %d+%d=%d",*r, *b, s);
}
else if (g==2)
{
s=Subtraction(r,b);
printf("The Subtraction result is %d-%d=%d",*r, *b, s);
}
else if (g==3)
{
s=Devision(r,b);
printf("The Devision result is %d/%d=%d",*r, *b, s);
}
else if (g==4)
{
Multiplication(r,b);
printf("The Multiplication result is %d/%d=%d",*r, *b, s);
}
else
{
break;
}
return 0;
}
}
主函数结束。 以下是所有其他功能
Addition()
{
int x;
printf("Ennter first nr: ");
scanf("%d",&n);
printf("Ennter second nr: ");
scanf("%d",&p);
x=n+p;
return x;
}
Subtraction()
{
int x;
printf("Ennter first nr: ");
scanf("%d",&n);
printf("Ennter second nr: ");
scanf("%d",&p);
x=n-p;
return x;
}
Devision()
{
int x;
printf("Ennter first nr: ");
scanf("%d",&n);
printf("Ennter second nr: ");
scanf("%d",&p);
x=n / p;
return x;
}
Multiplication()
{
int x;
printf("Ennter first nr: ");
scanf("%d",&n);
printf("Ennter second nr: ");
scanf("%d",&p);
x=n * p;
return x;
}
最佳答案
1) 刷新有关指针的知识,如果需要,可以通过指针
传递参数。
间接或取消引用运算符*
给出指针所指向的对象的内容。
一元或一元运算符&
给出变量的地址。
2) 避免全局变量在 main
之后在本地声明。
3) 使用switch
代替if-else
链
#include <stdio.h>
#include <stdlib.h>
int Addition(int* n, int* p)
{
int x;
printf("Ennter first nr: ");
scanf("%d",n);
printf("Ennter second nr: ");
scanf("%d",p);
x = *n + *p;
return x;
}
int Subtraction(int* n, int* p)
{
int x;
printf("Ennter first nr: ");
scanf("%d",n);
printf("Ennter second nr: ");
scanf("%d",p);
x = *n - *p;
return x;
}
int main(void)
{
int n1 = 0;
int n2 = 0;
int *r = &n1;
int *b = &n2;
int g,s;
while (1)
{
printf("Please choose the Arithmetic operation: \n");
printf("Addition-> 1 \nSubtraction-> 2 \nDevision-> 3 \nMultiplication-> 4 \nExit-> 0\n ");
scanf("%d",&g);
switch(g)
{
case 0:
printf("END\n");
return 0;
break;
case 1:
s = Addition(r, b);
printf("The addition result is: %d+%d=%d\n\n",n1, n2, s);
break;
case 2:
s = Subtraction(r ,b);
printf("The Subtraction result is: %d-%d=%d\n\n",*r, *b, s);
break;
}
}
return 0;
}
测试:
Please choose the Arithmetic operation:
Addition-> 1
Subtraction-> 2
Devision-> 3
Multiplication-> 4
Exit-> 0
2
Ennter first nr: 5
Ennter second nr: 3
The Subtraction result is: 5-3=2
Please choose the Arithmetic operation:
Addition-> 1
Subtraction-> 2
Devision-> 3
Multiplication-> 4
Exit-> 0
0
END
关于在c中本地使用指针调用和返回函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49233929/