我正在制作一个程序，其中我必须生成 N*N 的二维数组，其中包含随机数而不重复，以便一个元素是字母表。
此外，如果矩阵大小为 3，则元素必须介于 1 到 8 之间，且不重复且为单个字母。
类似地，对于大小为 4 的矩阵，元素必须介于 1 到 15 之间，且不能重复且为单个字母。
有人可以帮忙吗？
[代码]
#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
main()
{
int i,j,b,c,n ;
char ar[100][100];
char temp,ch;
printf("enter the size of the matrix : ");
scanf("%d",&n);
for(i=0;i<n;i++)
{
printf("\n");
for(j=0;j<n;j++)
{
scanf("%d",&ar[i][j]);
printf("\t");
}
}
ar[n-1][n-1] = 'E';
// for printing the array
for(i=0;i<n;i++)
{
printf("\n");
for(j=0;j<n;j++)
{
if(i==(n-1)&&j==(n-1))
{
printf("%c",ar[n-1][n-1]);
}
else
printf("%d",ar[i][j]);
printf("\t");
}
}
printf("\n Press 'w' for shifting up 's' for down 'a' for left and 'd' for right : \n");
while(1) //infinite loop
{
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(ar[i][j]=='E')
{
b = i; //storing row
c = j; // storing column
printf("\t");
ch = getch();
switch(ch)
{
case 'w':
if((i-1)>=0)
{
system("CLS");
temp = ar[i-1][j];
ar[i-1][j] = ar[i][j];
ar[i][j] = temp;
for(i=0;i<n;i++)
{
printf("\n");
for(j=0;j<n;j++)
{
if(i==(b-1)&&j==c)
{
printf("%c",ar[n-1][n-1]);
}
else
printf("%d",ar[i][j]);
printf("\t");
}
}
printf("\t");
}
else
{
printf("wrong move bro");
}
break;
case 'a':
if((j-1)>=0)
{
system("CLS");
temp = ar[i][j-1];
ar[i][j-1] = ar[i][j];
ar[i][j] = temp;
for(i=0;i<n;i++)
{
printf("\n");
for(j=0;j<n;j++)
{
if(i==b&&j==(c-1))
{
printf("%c",ar[n-1][n-1]);
}
else
printf("%d",ar[i][j]);
printf("\t");
}
}
printf("\t");
}
else
{
printf("wrong move bro");
}
break;
case 's' :
if((i+1)<n)
{
system("CLS");
temp = ar[i+1][j];
ar[i+1][j] = ar[i][j];
ar[i][j] = temp;
for(i=0;i<n;i++)
{
printf("\n");
for(j=0;j<n;j++)
{
if(i==(b+1)&&j==c)
{
printf("%c",ar[n-1][n-1]);
}
else
printf("%d",ar[i][j]);
printf("\t");
}
}
printf("\t");
}
else
{
printf("wrong move bro");
}
break;
case 'd' :
if((j+1)<n)
{
system("CLS");
temp = ar[i][j+1];
ar[i][j+1] = ar[i][j];
ar[i][j] = temp;
for(i=0;i<n;i++)
{
printf("\n");
for(j=0;j<n;j++)
{
if(i==b&&j==(c+1))
{
printf("%c",ar[n-1][n-1]);
}
else
printf("%d",ar[i][j]);
printf("\t");
}
}
printf("\t");
}
else
{
printf("\n wrong move bro");
}
break;
} //switch end
} //if end
} //for end
} //for end
} //while end
} // main end
[/代码]
最佳答案
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <limits.h>
#include <errno.h>
typedef struct no_dup_rand {
size_t size;
int *data;
} NDR;
NDR *NDR_new(int start, int end);
int NDR_rand(NDR *ndr);
void NDR_drop(NDR *ndr);
int main(void){
int ar[100][100];
int i, j, n;
NDR *ndr;
srand(time(NULL));
printf("enter the size of the matrix : ");
scanf("%d", &n);
ndr = NDR_new(1, n*n-1);//specify the range
for(i = 0; i < n; ++i){
for(j = 0; j < n; ++j){
if(i != n-1 || j != n-1)
ar[i][j] = NDR_rand(ndr);//the one number of the specified range will be returned at random
}
}
ar[n-1][n-1] = 'E';
NDR_drop(ndr);//Disposal
for(i = 0; i < n; ++i){
for(j = 0; j < n; ++j){
if(i != n-1 || j != n-1)
printf("%d ", ar[i][j]);
else
printf("%c", ar[i][j]);
}
putchar('\n');
}
return 0;
}
NDR *NDR_new(int start, int end){//range : start <= r <= end
int i,v;
NDR *ret = malloc(sizeof(*ret));
ret->size = end - start + 1;
ret->data = malloc(ret->size * sizeof(int));
for(i=0, v=start; v <= end; ++v)
ret->data[i++] = v;
return ret;
}
void NDR_drop(NDR *ndr){
free(ndr->data);
free(ndr);
}
int NDR_rand(NDR *ndr){
if(ndr->size){
size_t i = rand() % ndr->size--;//note : assert(RAND_MAX >= ndr->size)
int ret = ndr->data[i];
ndr->data[i] = ndr->data[ndr->size];
return ret;
}
fprintf(stderr, "empty!\n");
errno = ERANGE;
return INT_MIN;
}
关于c - 需要生成二维数组中的随机数，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/28179110/