C++ 子结构

Question

嘿，我想获得一些有关子结构的帮助。 我按照以下说明进行锻炼: 有 1 个库

该图书馆有 10 位作者(书籍作者)

每个图书作者最多可以拥有 15 本书。

我必须使用两个函数: - 阅读所有信息 - 将书籍从 A 到 Z 排序

我现在写了结构，但由于子结构，我迷失了如何阅读它们

代码在这里:http://pastebin.com/gMaZXR89

这就是我已经走了多远，我陷入了那些“得到”。 我将不胜感激任何帮助，谢谢

Answer 1

我想我解决了你的问题......

#include <iostream>
#include <stdio.h>
#include <cstring>
using namespace std;

struct Book
{
    char title[30];//unneceserly use Author author[30] because you refer at the book by its author
    float price;
    int year_of_publication;
};

struct Author
{
    char name[30],subname[30];
    int birth_date;
    Book x[14];//a max of 15 books/author
};

struct Library
{
    /*there are 10 book writers*/Author y[9];//because you defined struct Author now you can use it without struct.
};

void readBooks(struct Library lib/*there is a single library*/, const int n=10)//there are 10 book writers
{
    int i,j,how_many;
    for(i=0;i<n;i++)
    {
        cout<<"Input "<<i+1<<". authors name"<<endl;
        gets(lib.y[i].name);//you call the array y not the type Author...
        cout<<"Input "<<i+1<<". authors subname"<<endl;
        gets(lib.y[i].subname);
        cout<<"How many books author"<<i+1<<" write?";
        cin>>how_many;

        for(j=0;j<how_many;++j)
           {
              cout<<"Input "<<i+1<<". authors "<<j+1<<" book title "<<endl;
              gets(lib.y[i].x[j].title);
              cout<<"Input "<<i+1<<". authors "<<j+1<<" book price "<<endl;
              cin>>lib.y[i].x[j].price;
              cout<<"Input "<<i+1<<". authors "<<j+1<<" book year of publication "<<endl;
              cin>>lib.y[i].x[j].year_of_publication;
           }
    }
}
int main()
{
    Library l;//can`t write struct in front because it is defined up...
    readBooks(l);
    return 0;
}