对 *char 的字符分配不起作用

Question

这是我的 main.c 中使用的一个函数。问题出在char任务。

void takeTurn(int *iap, int *tile, char *cap) {
    //*iap is 1 right now

    printf("\nThe current active player is %d. His character is %c", *iap, *cap);
    //prints The current active player is 1. His character is q.

    if (*iap == 1) *cap == 'X';
    if (*iap == 2) *cap == 'O';

    printf("\nThe current active player is %d. His character is %c", *iap, *cap);.
    //prints The current active player is 1. His character is q.

    . . . 
}

需要做什么才能*cap分配正确的 char给合适的活跃玩家？

Answer 1

您正在使用 == 相等比较运算符，而应使用 = 赋值运算符。

更改这些语句:

*cap == 'X';
*cap == 'O';

改为这些:

*cap = 'X';
*cap = 'O';