c - 动态内存分配的二进制加法

Question

经过很长一段时间，我在 C 中使用动态内存分配，遇到了一些内存泄漏问题......我只是看不出问题可能出在哪里。有人可以帮忙吗？

编辑2: 现在，即使对于非常大的数字，该程序也可以正常工作，并且速度相当快:)我决定更改程序结构并使用 struct 而不仅仅是 char 字符串。不应该有任何内存泄漏(使用 valgrind 测试)。

当前代码:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct binary{
    char * number;
    size_t length;
}Tbinary;

//exterminate leading zeros
size_t exterminate(char * bin, size_t length){
char * pch = NULL;
long position = 0;

pch = strchr(bin, '1');
if(pch==NULL){
    bin[1] = '\0';
    length = 2;
}
else{
    position = pch-bin;
    strcpy(bin, pch);
}

return (length-position);
}

int binaryAdd(Tbinary first, Tbinary second){
int a=0, b=0, sum=0, carry=0;
size_t index = first.length;
first.number[first.length] = '\0';

while((first.length != 0) || (carry != 0)){
    if(first.length>1) a= first.number[first.length-2]-'0';
    else a = 0;
    if(second.length>1) b= second.number[second.length-2]-'0';
    else b = 0;
    sum = (a+b+carry)%2;
    first.number[first.length-1] = (sum)+'0';
    carry = (a+b+carry)/2;
    if(first.length >0)first.length--;
    if(second.length >0)second.length--;
}

exterminate(first.number,index);

printf("Sum: %s\n", first.number);
return EXIT_SUCCESS;
}

int get_number(Tbinary *bin_addr){
char * tmp, * bin;
char ch=1;
int size = 1, index = 0;
bin = bin_addr->number;

while(ch){
    ch = getc(stdin);

    if((ch == '\n') || (ch == ' ')) ch = '\0';

    if((ch-'0' != 0) && (ch-'0' != 1) && (ch != '\0')) return EXIT_FAILURE;

    if (size-1 <=index){
        size += 5;
        tmp = (char *)realloc(bin, size*sizeof(char));
        if(tmp == NULL){
            return EXIT_FAILURE;
        }
        bin = tmp;
        bin_addr->number = bin;
    }
    bin[index++] = ch;
}

bin_addr->length = index;
bin_addr->length = exterminate(bin_addr->number, bin_addr->length);

return EXIT_SUCCESS;
} 

int main (void)
{
Tbinary bin1 = {bin1.number = NULL, bin1.length = 0};
Tbinary bin2 = {bin2.number = NULL, bin2.length = 0};

//allocate space for first number
bin1.number = (char *)malloc(sizeof(char));
if(bin1.number == NULL)
    return EXIT_FAILURE;

//allocate space for second number
bin2.number = (char *)malloc(sizeof(char));
if(bin2.number == NULL){
    free(bin1.number);
    return EXIT_FAILURE;
}

printf("Enter two binary numbers:\n");

//number1 load
if(get_number(&bin1) != EXIT_SUCCESS){
    free(bin1.number);
    free(bin2.number);
    printf("Invalid input.\n");
    return EXIT_FAILURE;
}

//number2 load
if(get_number(&bin2) != EXIT_SUCCESS){
    free(bin1.number);
    free(bin2.number);
    printf("Invalid input.\n");
    return EXIT_FAILURE;
}

//add the two numbers
if(bin1.length >= bin2.length){
    if(binaryAdd(bin1, bin2) != EXIT_SUCCESS){
        free(bin1.number);
        free(bin2.number);
        printf("Invalid input.\n");
        return EXIT_FAILURE;
    }
}
else{
    if(binaryAdd(bin2, bin1) != EXIT_SUCCESS){
        free(bin1.number);
        free(bin2.number);
        printf("Invalid input.\n");
        return EXIT_FAILURE;
    }
}

free(bin1.number);
free(bin2.number);
return EXIT_SUCCESS;
}

Answer 1

在binaryAdd()中，在所有情况下，您都应该在realloc()之后释放总和，而不仅仅是当realloc()返回null时。 get_number() 中也是如此。 关于a = (int)strlen(first);为什么将strlen()的返回值转换为int？ 另外，不要强制转换分配函数的返回值。