c - 未定义对 "calcyear"的引用

Question

如果您无法通过我为您布置的高级代码来判断，我是编程新手。我正在读一本关于 C 编程的书，我从中复制了这段代码作为练习，但我不知道为什么会出现这样的错误。请帮忙!!!

我收到一条错误，指出 "file: main.c" "message: undefined reference to calcyear"

/*bigyear.c*/

 #include <stdio.h>
 #define TARGET_AGE 88

int year1, year2;

int calcYear(int year1);

int main(void)
{
    printf("What year was the subject born?");
    printf("Enter as a four digit year (YYYY):");
    scanf("%d", &year1);

    /*calculate the future year and display it*/
    year2 = calcYear(year1);

    printf("someone born in %d will be %d in %d.", year1, TARGET_AGE, year2);

    return 0;

    int calcYear(int year1)
    {
        return(year1+TARGET_AGE);
    }


}

Answer 1

在 main() 函数之外定义 int calcYear(intyear1)。

在标准 C 中，您不能在另一个函数中定义一个函数。