c - 确定数组(预定义数组)的奇数和偶数并将它们存储到 2 个单独的数组中

Question

嗨，我正在尝试确定数组(预定义数组)的奇数和偶数并将它们存储到 2 个单独的数组中，但存在一些问题。它没有显示正确的结果。请参阅此处:

#include <stdio.h>
#include <conio.h>

void main()
{
long int ARR[10]={2,5,4,7,8,0,9};
long int OAR[10], EAR[10];
int i, j = 0, k = 0, n;


for (i = 0; i <ARR[i]; i++)
{
    if (ARR[i] % 2 == 0)
    {
        EAR[j] = ARR[i];
        j++;
    }
    else
    {
        OAR[k] = ARR[i];
        k++;
    }
}

printf("The elements of OAR are \n");
for (i = 0; i < j; i++)
{
    printf("%ld\n", OAR[i]);
}
printf("The elements of EAR are \n");
for (i = 0; i < k; i++)
{
    printf("%ld\n", EAR[i]);
}
getch();
}

结果是:

The elements of OAR are
5
7
1995706722

The elements of EAR are
2
4

Answer 1

改变

for (i = 0; i <ARR[i]; i++)  
                 ^ Wrong  condition 

到

for (i = 0; i < 7; i++)  

并将数组OAR和EAR初始化为0:

long int OAR[10] = {0}, EAR[10] = {0};