c - 我在执行代码时收到段错误。有什么问题吗？

Question

我正在学习 C 编程并尝试编写计算代码。当我的程序运行时，我遇到段错误。

问题出在哪里？

#include<stdio.h>
#include<string.h>

int main()
{   
    int n,i,j,k; 
    int c,x[10];
    printf("Enter the number of springs ");                                 
    scanf("%d",&n);

    int f[n],s[n],A[n][n+1][n+2]; //declare my variables here

    memset(A, 0, n*n+1*n+2*(sizeof(A))); //put all to zeros

    //store datas for stiffness and strength

    for(i=1;i<=n;i++)
    { 
        printf("Enter the stiffness of spring %d\n",i);                 
        scanf("%d",&s[i]);
    }

    for(i=1;i<=n;i++)
    {
        printf("Enter the force applied to the spring %d\n",i); 
        scanf("%d",&f[i]);
    }

    for(i=1;i<=n;i++){
        printf("\nforce applied in f[i] = %d",f[i]);
    }


    //computation for element 1 matrix

    for(k=1;k<=n;k++)

    for(i=1;i<=n+1;i++)

    {
        for(j=1;j<=n+2;j++)
        { 
            if(j==k||j==(k+1))
               A[k][i][j]=s[j];

            if(j==n+3)
                A[k][i][j]=f[j];
        }  
    } 

    for(k=1;k<=n;k++)
    {
        printf("\nmy n=%d matrix is\n",k);

        for(i=1;i<=(n+1);i++)
        {
            for(j=1;j<=(n+2); j++)
                printf("%d\t", A[k][i][j]);

                printf("\n");
        }
     }

     return 0;
}

Answer 1

更改memset(A,0,n*n+1*n+2*(sizeof(A)));

到

memset( A,0,n*(n+1)*(n+2)*sizeof(int)); 

还有for循环初始化应该是 i=0;和状况i<n .