c - 如何在for循环中存储从rand()函数获得的数字？

Question

请告诉我如何存储从 g 获得的数字并打印它们:
示例:2,2,6

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char* argv[]) {
    int nrzaruri;
    int g;
    int valori;
    int array[g];
    printf("cate zaruri arunci?\n");
    scanf("%d", &nrzaruri);
    for (int i = 1; i <= nrzaruri; i++) {
        g = (rand() % 6) + 1;
        printf("zarul %d\n are valoarea %d\n", i, g);
    }
}

Answer 1

如果我理解正确，您需要的是以下内容

#include <stdio.h>
#include <stdlib.h>

int main(void)
{    
    int nrzaruri;

    printf( "cate zaruri arunci?\n" );
    scanf( "%d", &nrzaruri );

    int array[nrzaruri];

    for ( int i = 0; i < nrzaruri; i++ ) 
    {
        int g = ( rand() % 6 ) + 1;
        array[i] = g;
    }

    for ( int i = 0; i < nrzaruri; i++ ) 
    {    
        printf( "zarul %d\n are valoarea %d\n", i + 1, array[i] );
    }

    return 0;
}

您可以替换这两个语句

        int g = ( rand() % 6 ) + 1;
        array[i] = g;

对于这个

        array[i] = ( rand() % 6 ) + 1;

我只是使用了你的变量。

或者，如果您需要在一行中输出数组的元素，则可以使用以下循环

int i = 0;
do
{    
    printf( "%d", array[i] );
} while (  ++i < nrzaruri &&  printf( ", " ) > 0 );

输出将如下所示

2, 5, 4, 2, 6, 2, 5, 1, 4, 2