c - C中的猜谜游戏，无法获得有效的尝试次数，变量为 "counter"

Question

不太确定如何让计数器变量来计算猜对数字需要多少次尝试。我尝试过输入“counter++;”在每个 if 语句中，但这不会做任何事情。这是我自己编写的第一个代码，所以请不要拖得太紧<3

int main()
int counter
{
    int num , guess;
    counter = 0;
    srand(time(0));
    num = rand() % 200 + 1;

    printf ( "Guessing game, guess the number between 1 and 200" );

    do {
        scanf ( "%d" , &guess);
        if ( guess > num ){
        printf ( "Too high" );
    }

        if ( guess < num ){
        printf ( "Too low" );
    }

        if ( guess == num ){
        counter++;
        printf ( "Your guess is correct!, it took you %d tries" , counter );
        }


    }while (guess != num);

return 0;

}

Answer 1

只有当用户猜测正确时，您才会增加计数器。相反，您应该在每次尝试时增加它。

您的程序中存在语法错误。这是更正后的版本:

#include <stdio.h>

int main() {
    int counter = 0;
    int num, guess;

    srand(time(0));
    num = rand() % 200 + 1;

    printf("Guessing game, guess the number between 1 and 200");

    while (scanf("%d", &guess) == 1) {
        counter++;
        if (guess > num) {
            printf("Too high\n");
        }
        if (guess < num) {
            printf("Too low\n");
        }
        if (guess == num) {
            printf("Your guess is correct! it took you %d tries\n", counter);
            return 0;
        }
    }
    printf("Invalid input\n");
    return 1;
}