我编写了一个C程序,该程序将模拟用户输入的X年期间的彩票抽奖,一旦输入了年数,它将模拟每周的抽奖,无论多少年。 程序还需要打印出预先输入的数字(已经在代码中)是否匹配,以及打印出数字匹配的次数,例如
- 6 个号码匹配 ()
- 5 个号码匹配 ()
- 等等
这是我到目前为止的代码,一切都编译并运行良好:
#include <stdio.h>
int main(int argc, char const *argv[])
{
//Welcome the User to the Program
puts("============================");
puts(" WELCOME TO ");
puts("============================");
puts(" PROJECT : JACKPOT DREAMS ");
puts("============================");
//Rogers 6 Original Numbers
int nums[6] = { 5, 11, 15, 33, 42, 43 };
//Ask how many years to simulate
int years = 0;
printf("How many years would you like to sleep for? :\n");
scanf("%d", &years);
printf("Ok. I will now play the lottery %d year(s)\n",years);
printf("Sleep Tight :)....\n");
//Generate Random Numbers
int ctr;
int randnums[6];
srand(time(NULL));
while (years-- > 0) {
for( ctr = 0; ctr < 6; ctr++ ) randnums[ctr] = (rand() % 50);
//Check Numbers with Rogerns numbers
int win = 1;
for( ctr = 0; ctr < 6; ctr++ )
{
if(randnums[ctr] != nums[ctr])
{
win = 0;
break; // if there's a mismatch we don't need to continue
}
}
return 0;
}
}
有人知道我该怎么做吗?
最佳答案
首先,您似乎在循环第一年之后返回
。您应该将 return
语句移到大括号之外。其次,正如一些评论提到的,您应该更仔细地编写 block ,并进行正确的缩进。
下面我重写了您的程序,以打印出某些数字是否与给定年份匹配。如果所有数字都匹配,则“获胜!”也被打印。为此,我添加了一些变量和 print
语句。
希望这有帮助。
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int
main(int argc, char const *argv[])
{
//Welcome the User to the Program
puts("============================");
puts(" WELCOME TO ");
puts("============================");
puts(" PROJECT : JACKPOT DREAMS ");
puts("============================");
//Rogers 6 Original Numbers
int nums[6] = { 5, 11, 15, 33, 42, 43 };
//Ask how many years to simulate
int years = 0;
printf("How many years would you like to sleep for? :\n");
scanf("%d", &years);
printf("Ok. I will now play the lottery %d year(s)\n",years);
printf("Sleep Tight :)....\n");
//Generate Random Numbers
int numberOfWins = 0;
int ctr;
int randnums[6];
srand(time(NULL));
int currYear = 0;
while (years-- > 0)
{
currYear++;
for( ctr = 0; ctr < 6; ctr++ ) randnums[ctr] = (rand() % 50);
//Check Numbers with Rogerns numbers
int win = 1, matched = 0;
for( ctr = 0; ctr < 6; ctr++ )
{
if(randnums[ctr] != nums[ctr])
{
win = 0;
} else {
matched++;
}
}
numberOfWins += win;
//If any numbers matched or win, print it.
if (matched > 0) printf("In year: %d, %d number(s) matched\n", currYear, matched);
if (win) printf("Winner!\n");
}
printf("You won %d time(s)\n", numberOfWins);
return 0;
}
关于c - 如何? - 彩票模拟(C),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55282072/