c - 用c猜数字程序

Question

我需要编写一个程序，当计算机选择从1到100的数字时，玩“猜数字”游戏，用户有10次尝试，如果他猜的数字太小，每轮用户都会收到输出或太大，或者是幸运数字，请帮忙

这就是我到目前为止所做的...

#include <stdio.h>
#include <stdlib.h>

void main() {


    int i ,guess=0 , lucky=rand()%100;
    for (i = 0; i <= 10; i++) {
        printf("please enter your guess\n");
        scanf("%d",&guess);



        }
}

Answer 1

这应该适合你!

#include <stdio.h>
#include <stdlib.h>

int main() {

    srand(time(NULL));
    int count , guess = 0, lucky = rand() % 101;


    for (count = 0; count < 10; count++) {
        printf("please enter your guess\n>");
        scanf("%d", &guess);

        if(guess == lucky) {
            printf("WIN");
            break;
        }

        if(guess > lucky)
            printf("too big\n\n");
        else
            printf("too small\n\n");

    }

    if(count == 10)
        printf("FAIL");


    return 0;

}