c - 我收到运行时错误，我无法获取两个字符值 a 和 b

Question

如果我为变量 s 提供输入“hello”，为变量提供 a 我无法提供输入

#include<stdio.h>
#include<string.h>
int main(){
    char s[100],a,b;
    //i am not able to get this value,please help me how to get three variables s,a,b at runtime
    scanf("%c",s);
    scanf("%c",a);
    scanf("%c",b);
    int n=strlen(s),count=0;
    for(int i=0;i<n;i++){
        if(s[i]==a && s[i+1]== b)
            count++;
    }
    printf("%d",count);
    return 0;
}

Answer 1

首先尝试使用 scanf("%c",&a) scanf 。 然后仅使用一个 scanf 读取三个变量。 试试这个程序，它将解决您的问题:

#include <stdio.h>
#include <string.h>
int main()
{
    char s[100], a, b;
    //i am not able to get this value,please help me how to get three variables s,a,b at runtime
    scanf("%s %c %c", s, &a, &b);
    int n = strlen(s), count = 0;
    for(int i = 0; i < (n - 1); i++){
        if(s[i] == a && s[i+1] == b)
            count++;
    }
    printf("%d",count);
    return 0;
}