c - 将文件 'filename' 读入字符缓冲区 'text'

Question

我想知道如何从 Bash shell 的命令行运行此 C 代码？

#include <stdlib.h>
#include <stdio.h>
#include <ctype.h>

/* Size of character buffer to read in a file. */
#define BUFFSIZE 1000000

/* Read file 'filename' into character buffer 'text'.*/

long read_file(char *filename, char *text ) {
FILE *fp   = fopen(filename, "r");
   long  size = 0; // Number of characters read.
   len  = 0;

if (fp == NULL) {
    fprintf(stderr, 
            "Error could not open file: %s\n", 
            strerror(errno));
    return -1;
}

/* Go to the end of the file. */
if (fseek(fp, 0L, SEEK_END) == 0) {
    /* Get the size of the file. */
    size = ftell(fp);
    if (size == -1) {
        fprintf(stderr, 
                "Error could not open file: %s\n",
                 strerror(errno));
        return -1;
    }

    /* Go back to the start of the file. */
    if (fseek(fp, 0L, SEEK_SET) != 0) {
        fprintf(stderr, 
                "Error rewinding to start of file: %s\n",
                 strerror(errno));
        return -1;
    }

    /* Read the entire file into memory. */
    len = fread(text, sizeof(char), (size_t)size, fp);
    if (len == 0) {
        fprintf(stderr, 
                "Error reading file into memory: %s\n", 
                 strerror(errno));
        return -1;
    } else {
       text[++len] = '\0'; /* Add a null-terminator. */
    }
}
(void)fclose(fp);
return size;
}

这就是文件中的所有代码，只是不确定我使用的命令，因为我已经使用过: chmod +x filename 使其可运行，然后我输入 ./filename 来运行，但只是收到错误消息，所以有我做错了什么，我只是不知道那是什么

Answer 1

你的代码编译了吗？尝试gcc <file.c> -o <outputName>